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## Homework Statement

A curve is given by the parametric equations

##x=t^2 +3##

##y=t(t^2+3)##

Find dy/dx in terms of t and show that (dy/dx)^2 >=9

## Homework Equations

Parametric derivatives

## The Attempt at a Solution

Using the chain rule, I arrived at ##\frac{dy}{dx}=\frac{3}{2}(\frac{t^2+1}{t})##

However, when I squared both sides to get ##(\frac{dy}{dx})^2##, I was unable to prove that (dy/dx)^2>=9. I know I need to find the range, however I'll need to graph the function, which proves to be tedious. Is there any workaround to this?