Finding the Rate of Change of Area in a Changing Triangle

Click For Summary

Homework Help Overview

The discussion revolves around finding the rate of change of the area of a triangle when two sides and the included angle are changing over time. The original poster describes specific rates of change for the angle and the sides, along with particular measurements at a given moment.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of the cosine law to find the length of the third side of the triangle and question whether the area formula can be applied without a right angle. There are suggestions to use trigonometric relationships to express the area in terms of the known sides and angle.

Discussion Status

Participants are exploring different methods to approach the problem, including the application of the cosine law and trigonometric functions. Some guidance has been offered regarding the use of area formulas and differentiation, but there is no explicit consensus on a single method yet.

Contextual Notes

There is a mention of uncertainty regarding the angle type and the specific formula to use for the area, indicating that assumptions about the triangle's properties are under discussion.

maymay43465
Messages
2
Reaction score
0
Need help guys, not understanding this at all. Can anyone help me out?

Two sides of a triangle and their included angle are changing with respect to time. The angle increases at the rate of 1 radian/sec, one side increases at the rate of 3ft/sec, and the other side decreases at the rate of 2ft/sec. Find the rate at which the area of the triangle is changing when the angle is 45 degrees, the first is 4 feet long and the second side is 5 feet long. Is the area increasing or decreasing at this instant?
 
Physics news on Phys.org
Since you are "given"the length of two sides and the angle between them, it shouldn't take too much to see that the cosine law gives you the length of the opposite side. Do you know a formula for the area of a triangle, given the lengths of the three sides? The derivative of both sides of that area formula, with respect to t should give you what you want.
 
question

Even if I am not sure I have a 90 degree angle this will work?
 
?? Did I say anything about a right angle? The "cosine law" works for any triangle, not just a right triangle. I was thinking about using the cosine law to find the length of the third side in terms of the other two and the angle between them, then using "Hero's formula" for the area.

Here is a much simpler way: first draw a picture. Draw your triangle with side of given length "a" as the base, the side with given length "b" going up from it and given angle [itex]\theta[/itex] between them. You know, I hope, that the area of a triangle is "1/2 base times height". You already have "a" as the length of the base. The "height" is measured perpendicular to the base so drop a perpendicular from the end of the second side to the base. The second side is then the hypotenuse, of length b, of a right triangle with angle [itex]\theta[/itex]. Use trig to write the "altitude", the length of that perpendicular as a function of b and [itex]\theta[/itex]. Now write the equation for the area of the triangle as a function of a, b, and [itex]\theta[/itex]. Differentiate that with respect to time to get the rate of change of area.
 

Similar threads

Replies
6
Views
1K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 3 ·
Replies
3
Views
8K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
Replies
6
Views
2K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
9K