Finding the ratio of the emfs of two cells by a potentiometer

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Discussion Overview

The discussion revolves around understanding the principles of a potentiometer in measuring the electromotive forces (emfs) of two primary cells connected in series, both with the same and opposite polarities. Participants explore the reasoning behind the addition and subtraction of emfs in different configurations and seek intuitive explanations for the observed results.

Discussion Character

  • Exploratory
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant expresses confusion about why the emfs E1 and E2 are added when connected with the same polarity and subtracted when connected with opposite polarities.
  • Another participant asks for a circuit diagram to clarify the setup involving the cells, potentiometer, and galvanometer.
  • A participant indicates they have calculated the ratio of the emfs as 4:3 but seeks a deeper understanding of the underlying principles.
  • There is a suggestion to consider Kirchhoff's laws to aid in understanding the problem.
  • Participants discuss the process of sharing circuit diagrams and attachments to facilitate the discussion.

Areas of Agreement / Disagreement

Participants generally agree on the basic principles of potentiometers and the calculations involved, but there remains uncertainty about the intuitive understanding of why the emfs behave differently based on their connection polarity. The discussion does not reach a consensus on a clear explanation.

Contextual Notes

Participants express limitations in their understanding of the intuitive reasoning behind the addition and subtraction of emfs, indicating a need for further clarification of the concepts involved.

betaleonis
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I don't have a clear perception of how the following question is answered:

"Two primary cells of emfs E1 and E2 respectively are joined in series with (i) the same polarity, and (ii) opposite polarities. The combination is connected through a galvanometer and a jockey to a potentiometer. The balancing lengths in the two cases are found to be 350 cm and 50 cm respectively. Find the ratio of E1 and E2."

With a little bit of calculation I get the answer, 4:3. With the knowledge of the basic principle of potentiometer and from what I have learned from my physics textbook, the sum of the two emfs is proportional to the length given in the first case, and when E2 is subtracted from E1, the result is proportional to the length given in the second case. I don't quite understand why the emfs are added when they are joined with the same polarity and subtracted when they are joined the other way round.
 
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Welcome to PF.
Is this a homework problem?
Can you draw the circuit diagram showing how you connect the cells, potentiometer and galvanometer.
 
Thanks for the reply.

Yes, it can be viewed as a homework problem (though answering the question isn't exactly part of my homework).

I have roughly drawn the following circuit diagrams in reference to the question:

https://www.physicsforums.com/attachment.php?attachmentid=71449&stc=1&d=1405709293
 
To attach a file, while posting by “Quick Reply” or “Edit” a recent post, click “Go Advanced”,
then scroll down to “Additional Options”, “Attach Files”, click “Manage Attachments”.
Click “Browse”, select your file, then click “Upload”. Wait till done, then “Close this window”.
“Preview Post” and you will see your file attached.
 
I did that at first; but ended up opening the file in another tab, copying its URL, inserting it in that post, and deleting the attachment. :redface: My apologies.
 
So, you've worked this out now?
 
I know the answer to the question and how to answer it, but I don't have an intuitive explanation as to why I answered it like the way I did. I still don't know why E2 is added to and subtracted from E1 in the first case and second case respectively. Also, is there any other way to come up with a solution?
 

Attachments

  • PF.jpg
    PF.jpg
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Does the attached file help?
Think of the V axis as the potentiometer wire.
 

Attachments

  • Sum&Diff.jpg
    Sum&Diff.jpg
    22.3 KB · Views: 652
Thank you. :approve:
 
  • #10
It may help to think in terms of Kirchoff 2 in problems like this one.
 

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