1. The problem statement, all variables and given/known data Determine the real part, the imaginary part, and the absolute magnitude of the following expressions: tanh(x-ipi/2) cos(pi/2-iy) 2. Relevant equations cos(x) = e^ix+e^-ix tanh(x) = (1-e^-2x)/(1+e^-2x) 3. The attempt at a solution for cos(pi/2-iy)= (e^(ipi/2-i^2(y))+e^(i^2(y)-ipi/2))/2 =0.5(e^ipi/2*e^-i^2y + e^i^2y*e^-ipi/2) =0.5(ie^y+e^-y*-i) =0.5i(e^y-e^-y) therefore, imaginary = 0.5(e^y-e^-y) and real = 0 for tanh(x-ipi/2) = (1-e^-2(x-ipi/2))/(1+e^-2(x-ipi/2)) after simplifying i get (1+e^-2x)/(1-e^-2x) so that ^ is the real part and imaginary = 0 I'm not really sure if im doing this right though, or if i have to somehow simplify these expressions to get the answer. If so, how would I solve the question?