MHB Finding the real and imaginary parts of a function

shen07
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If f:C-->C is holomorphic and View attachment 1263 , find the real and imaginary parts ug and vg of g in terms of the real and imaginary parts uf and vf of f.
 

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Re: Please can you give me some hint to do this exercise

For clarification you mean by $$u_g=\text{Re}(g) $$ and $$v_g=\text{Im}(g)$$ using that $$g(x,y) = u(x,y)+iv(x,y)$$ , right?
 
Re: Please can you give me some hint to do this exercise

ZaidAlyafey said:
For clarification you mean by $$u_g=\text{Re}(g) $$ and $$v_g=\text{Im}(g)$$ using that $$g(x,y) = u(x,y)+iv(x,y)$$ , right?

yeas right
 
Re: Please can you give me some hint to do this exercise

I would suggest starting by

$$u_f = \frac{f(z)+\overline{f(z)}}{2}$$
 
Re: Please can you give me some hint to do this exercise

ZaidAlyafey said:
I would suggest starting by

$$u_f = \frac{f(z)+\overline{f(z)}}{2}$$
One more question what is $$\overline{f(\overline{z})}$$ actually?? i don't quite understand this!
 
Re: Please can you give me some hint to do this exercise

shen07 said:
One more question what is $$\overline{f(\overline{z})}$$ actually?? i don't quite understand this!
Consider a simple example:
f(z) = u(z) + i v(z) with z = x + iy.

Then
f(z) = u(x + iy) + i v(x + iy)

f( \overline{z} ) = u(x - iy) + i v(x - iy)

\overline{f( \overline{z} ) } = u(x - iy) - i v(x - iy)

Is this what you are looking for? Or something more conceptual?

-Dan
 
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Another example:
$$f(z)=z^2+i \Rightarrow \overline{f\left({\bar{z}}\right)}=\overline{(\bar{z})^2+i}=\overline{ \overline{z^2}+i}=\overline{\overline{z^2}}+\bar{i}=z^2-i$$
 
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