Finding the resultant couple moment

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SUMMARY

The discussion focuses on calculating the resultant couple moment using two forces, 150 N and 200 N, with distances derived from Pythagorean theorem as sqrt32 and sqrt8. The user initially calculated the moments as M1 = 150*sqrt32 and M2 = 200*sqrt8, leading to a resultant moment of 283 Nm clockwise. However, the correct method involves breaking the couples into their x and y components, emphasizing the importance of using the distance between the lines of application of the forces rather than the distances between the points of application.

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theBEAST
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Homework Statement


I attached the question as a picture to this thread

Homework Equations


M=Fd

The Attempt at a Solution


I was taught that the moment produced by two equal but opposite forces is the magnitude of one force multiplied by the distance between the two forces.

I used Pythagoras to solve for the distances between each of the couples and found sqrt32 and sqrt8 to be these distances.

Thus
M1= 150*sqrt32
M2=200*sqrt8

and the resultant moment
=M1-M2
=283Nm [clockwise]

This is not the answer, the method the answer key used was breaking up the couples into x and y. I don't understand why my method does not work as well.
 

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hi theBEAST! :smile:
theBEAST said:
… the distances between each of the couples and found sqrt32 and sqrt8 to be these distances.

nooo :redface:

√32 and √8 are the distances between the points of application of these forces

the couple uses the distance between the lines of application of the forces :wink:
 

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