Finding the set of interior points, the closure, and an example

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Homework Help Overview

The discussion revolves around the set S defined as S=[0,1)∪(1,2) and involves identifying the set of interior points, the closure of the set, and providing examples of sets with specific properties related to interior and closure points.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definition of interior points and closure, questioning whether certain intervals are contained within S and whether proposed examples meet the criteria outlined in the problem.

Discussion Status

Participants are actively engaging with the definitions and properties of sets, with some providing answers and others questioning the validity of those answers. There is a recognition of the need for clarification regarding the examples given, particularly in relation to the properties of closure and interior points.

Contextual Notes

There is an ongoing examination of the definitions of interior points and closure, with participants noting specific elements that are included or excluded from the set S. Some participants express uncertainty about the correctness of their examples and the implications of their definitions.

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Suppose that S=[0,1)U(1,2)

a) What is the set of interior points of S?

I thought it was (0,2)


b) Given that U is the set of interior points of S, evaluate U closure.

I thought that U closure=[0,2]


c) Give an example of a set S of real numbers such that if U is the set of interior points of S, then U closure DOES NOT equal S closure

This one I was not sure about, but here is my example:
S=(0,3)U(5,6) S closure=[0,3]U[5,6]
U=(0,6) U closure=[0,6]

d) Give an example of a subset S of the interval [0,1] such that S closure=[0,1].

I said if the subset S=(0,1/2)U(1/2,1) then S closure=[0,1]

Are my answers right for these? If not could you please explain what the answer is in detail?
 
Last edited:
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If S=[0,1)U(1,2), as you wrote, is (1/2, 3/2) contained in S? (Note that 1 is an element of (1/2, 3/2)).
 
I think so, when I read the problem that's all it had was S=[0,1)U(1,2). So I am assuming (1/2,3/2) is contained in S.
 
OK, assume (1/2, 3/2) is an open subset of S. Since 1 is an element of (1/2, 3/2), can this statement be true?
 
no it can't because 1 is not included in S
 
Last edited:
OK, so, can (0, 2) be the interior of S?
 
no, (0,2) can't be the interior of S. So it would be (0,1)U(1,2)?
 
Yes. The closure of S you wrote down is correct. Note that a useful fact about closures is that a point is in the closure of a set if and only if every neighbourhood of that point intersects the set of interest. So, 1 is in the closure of S.
 
So the closure is [0,2].

Was the example i gave for part C correct?
 
  • #10
Is it even possible to find an example for part c? I know the example I gave is wrong.
 
  • #11
Can it be correct, considering all we said in between?
 
  • #12
no, because some of the points in U (set of interior points)are not included in the original set S.
 

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