Finding the Slope of Tangent Line for Polar Curves

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SUMMARY

The discussion focuses on calculating the slope of the tangent line for polar curves using the formula dy/dx = [f'(theta)sin(theta) + f(theta)cos(theta)] / [f'(theta)cos(theta) - f(theta)sin(theta)]. Participants clarify that the formula is applicable only when a specific polar equation is provided. The user seeks assistance in understanding how to derive this formula using the relationships x = r cos(theta) and y = r sin(theta), along with the derivatives dy/dtheta and dx/dtheta.

PREREQUISITES
  • Understanding of polar coordinates and curves
  • Familiarity with differentiation and derivatives
  • Knowledge of trigonometric functions and their properties
  • Ability to manipulate equations involving x and y in polar form
NEXT STEPS
  • Study the derivation of dy/dx for polar curves in detail
  • Explore examples of specific polar equations and their tangent slopes
  • Learn about the applications of polar coordinates in calculus
  • Investigate the relationship between polar and Cartesian coordinates
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Students studying calculus, particularly those focusing on polar coordinates, as well as educators teaching the concepts of derivatives in polar systems.

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Homework Statement


Calculate a function of theta that gives the slope of the tangent line (dy/dx) to the polar curve r at some angle theta.


Homework Equations


dy/dx= f'(theta)sin(theta) + f(theta)cos(theta)/[f'(theta)cos(theta) - f(theta) sin(theta)]


The Attempt at a Solution


I am not even understanding what the question is asking. All I know is the formula above. Can someone please help me out? Thank you.
 
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That formula is the answer unless you are given some particular equation for the curve.
 
Oh, okay. So they are just asking for me to prove how I got to that using the x= r cos theta, y= r sin theta, and dy/dx= dy/dtheta / dx/dtheta formulas. Thank you!
 

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