- #1
Mr Davis 97
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I have the equation ##\sin 3x = \cos 7x##, and, in degrees, I have to find the smallest positive solution.
Immediately, we can see that sin and cos are equal if their arguments are complements, so ##3x + 7x = 90##, which means that ##x = 9##.
I know that that is a correct solution, but how do I show that it is, in fact, the smallest positive solution?
Immediately, we can see that sin and cos are equal if their arguments are complements, so ##3x + 7x = 90##, which means that ##x = 9##.
I know that that is a correct solution, but how do I show that it is, in fact, the smallest positive solution?