Finding the Sum of a Convergent Power Series

Click For Summary

Homework Help Overview

The discussion revolves around evaluating the sum of the series ∑ n².xⁿ for 0 < x < 1, focusing on the convergence properties and methods for deriving a function representation of the series.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore different methods to derive a function from the series, including differentiation and integration. There is a suggestion to start from a known series and manipulate it to find the desired expression.

Discussion Status

Participants are actively engaging with each other's suggestions, considering both differentiation and integration as potential approaches. There is recognition of different strategies being discussed without a clear consensus on the best method yet.

Contextual Notes

Some participants question the complexity of the original approach and suggest starting from simpler series. There is an emphasis on the need to derive expressions that can facilitate the evaluation of the series.

mathmathmad
Messages
50
Reaction score
0

Homework Statement



evaluate ∑ n^2.x^n where 0<x<1

Homework Equations





The Attempt at a Solution


let a_n = n^2 and c=0
then radius of convergence, R=1
hence the series convergences when |x|<1
let f(x) = ∑ n^2.x^n
then f'(x) = ∑ n^3.x^n-1 for n=0 to infinity
then f'(x) = ∑ (n+1)^3.x^n for n=1 to infinity

from here, how to I derive a function ∑ (n+1)^3.x^n so as to integrate it to get the sum?
 
Physics news on Phys.org
Hi mathmathmad! :smile:

(have an infinity: ∞ and try using the X2 and X2 tags just above the Reply box :wink:)
mathmathmad said:
let f(x) = ∑ n^2.x^n
then f'(x) = ∑ n^3.x^n-1 for n=0 to infinity
then f'(x) = ∑ (n+1)^3.x^n for n=1 to infinity …

Why are you making it more complicated? :redface:

Hint: try integrating. :wink:
 
differentiating is a much better option fyi
 
It's somewhat hard to start from your f(x) and find a series you know.

Instead, try starting from a series you know and apply these methods to get f(x).
 
what to integrate?
intergrate n^2.x^n?
 
mathmathmad said:
what to integrate?
intergrate n^2.x^n?

Sort-of.

Suppose it was ∑ nxn … what would you integrate? :wink:
 
I still say (expanding a little on my hint) to start with an expression for

∑ xn

and try to derive an expression for your series.
 
Hi Mathnerdmo! :smile:
Mathnerdmo said:
It's somewhat hard to start from your f(x) and find a series you know.

Instead, try starting from a series you know and apply these methods to get f(x).
Mathnerdmo said:
I still say (expanding a little on my hint) to start with an expression for

∑ xn

and try to derive an expression for your series.

ah, i see what you mean now …

your method is basically the same as mine, but in reverse …

i'm integrating the question to try to get something easier, while you're starting with something easier, and differentiating to get the question. :wink:

Yes, if mathmathmad wants to start with ∑ xn and differentiate it, that's fine. :smile:
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
7
Views
2K
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K