Finding the Sum of a Power Series: Tips and Tricks for Success

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Homework Help Overview

The original poster is attempting to find the sum of a power series that includes a factor of n². They express uncertainty about how to approach the problem, particularly regarding whether to break it down into two series.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of derivatives and suggest manipulating the series through differentiation. There are questions about the correctness of a derived result and requests for clarification on how certain steps were reached.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the series and questioning the validity of specific calculations. Some guidance has been offered regarding the use of derivatives, but there is no consensus on the correctness of the results presented.

Contextual Notes

There is mention of a specific value for x (1/10) and a reference to an external source (Wolfram) that suggests a discrepancy in the results. The original poster's attempts and the responses indicate a complex understanding of series manipulation is required.

peripatein
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Homework Statement


I am trying to find the sum of the series in the attachment.


Homework Equations





The Attempt at a Solution


I have tried to use various series and their derivatives, to not much avail.
I am not sure how to handle the n^2 factor.
Should I break it down to two series?
Any suggestions?
 

Attachments

  • Sum.jpg
    Sum.jpg
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You know about derivatives? Good do this

[tex]\sum_{k=1}^\infty k^2 x^{n-1}=\left( x \left( x \sum_{k=1}^\infty x^{k-1}\right)^\prime \right)^\prime=\left( x \left( x \frac{1}{1-x}\right)^\prime \right)^\prime[/tex]

|x|<1
your case will be x=1/10
 
If I am not mistaken, this yields 700/729, which, according to Wolfram, is incorrect. Would you please account for that?
 
peripatein said:
If I am not mistaken, this yields 700/729, which, according to Wolfram, is incorrect. Would you please account for that?

You are mistaken. Check it again.
 
Would you please explain how it was arrived at?
 
peripatein said:
Would you please explain how it was arrived at?

Basically you take x^(k-1). Multiplying by x and differentiating gives you k*x^(k-1). Doing the same thing again gives k^2*x^(k-1). Which is the form you want. Now sum the initial x^(k-1) as a geometric series and repeat the same sequence of operations on the function of you get.
 

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