Power series: x^3/3 + x^9/9 + x^15/15 .......

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Homework Help Overview

The discussion revolves around identifying a function represented by a specific power series: x^3/3! + x^9/9! + x^15/15! ... Participants are exploring the connections to known power series, particularly that of e^x, while grappling with the implications of the series' structure.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Some participants suggest examining the relationship between the terms of the series and the power series expansion of e^x. Others propose differentiating the series multiple times to uncover a differential equation that the function might satisfy.

Discussion Status

Participants are actively engaging with the problem, offering various approaches such as differentiation and examining derivatives. There is a recognition of a potential differential equation involving the function, but no consensus has been reached on how to proceed or resolve the problem.

Contextual Notes

The discussion is framed within the context of homework help, with participants noting the absence of a formal homework template and exploring the implications of the series' terms and their derivatives.

Shubhan672
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Moved from technical forum section, so missing the homework template

Let x be a real number. Find the function whose power series is represented as follows: x^3/3! + x^9/9! + x^15/15! ...

I see that there is a connection to the power series expansion of e^x but am having difficulty finding the function.
 
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Shubhan672 said:
Moved from technical forum section, so missing the homework template
Let x be a real number. Find the function whose power series is represented as follows: x^3/3! + x^9/9! + x^15/15! ...

I see that there is a connection to the power series expansion of e^x but am having difficulty finding the function.
Notice that ##x^3 = (x^3)^1## and ##x^9 = (x^3)^3##. Does that give you any ideas?
 
Try differentiating the series multiple times and see if you can determine a differential equation it satisfies.
 
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vela said:
Try differentiating the series multiple times and see if you can determine a differential equation it satisfies.
f(x) =
1581222250175.png


f'(x) =
1581222301684.png


f''(x) =
1581234957297.png


I can see that the 6 th, 12th, 18th ... derivative of f(x) would be f(x) itself but am having difficulty understanding its relevance and am having difficulty proceeding from here,
 

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Shubhan672 said:
f(x) = View attachment 256852

f'(x) = View attachment 256853

f''(x) = View attachment 256862

I can see that the 6 th, 12th, 18th ... derivative of f(x) would be f(x) itself but am having difficulty understanding its relevance and am having difficulty proceeding from here,

##f^{(6)}(x) = f(x)## is a differential equation. Can you solve it?

Hint: complex roots of unity.
 
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