Finding the Sum of an Infinite Series: \sum_{0}^{\infty} \frac {n^2} {3^n}

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Homework Help Overview

The discussion revolves around finding the sum of the infinite series \(\sum_{0}^{\infty} \frac {n^2} {3^n}\), which falls under the subject area of series and sequences in calculus.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster expresses uncertainty about how to approach the problem and mentions a preliminary guess based on the sum of the first ten terms. Some participants suggest using geometric series and derivatives as potential methods to explore the series further.

Discussion Status

Participants are exploring various mathematical techniques, including the multiplication of geometric series and differentiation, to find a viable approach to summing the series. There is no explicit consensus yet, but multiple lines of reasoning are being discussed.

Contextual Notes

There is a mention of using derivatives and the structure of geometric series, indicating that participants are considering advanced mathematical tools, but the original poster's lack of direction suggests some constraints in their understanding of the topic.

wilcofan3
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Homework Statement



Find the sum [tex]\sum_{0}^{\infty} \frac {n^2} {3^n}[/tex]

Homework Equations


The Attempt at a Solution



I don't know how to go about finding this sum, I have a guess of what it will be just by adding the first ten terms or so, but how do I find an actual approximation?
 
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Try multiplying three geometric series together and see how close it is to the above series. I think it's simmilar to repeated roots in differential equations.
 
John Creighto said:
Try multiplying three geometric series together and see how close it is to the above series. I think it's simmilar to repeated roots in differential equations.

The only similar series I see here are:

[tex]\sum_{0}^{\infty} (\frac {1} {3})^n[/tex]

[tex]\sum_{0}^{\infty} n^2[/tex]
 
Try looking at the second derivative of [tex]\sum_0^\infty x^n[/tex].
 
homogeneous differentiation

sum=[(xD)^2](1/(1-x))|x=1/3

that is
sum=g(1/3)
when
f(x)=1/(1-x)
and
g(x)=x[x*f'(x)]'=(x^2)*f''(x)+x*f'(x)
 
Last edited:

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