Finding the supremum of a 4D epsilon neighborhood

  • Thread starter bobbarker
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  • #1
bobbarker
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Homework Statement



Find sup{[tex]\epsilon[/tex]| N[tex]\epsilon[/tex](X0 [tex]\subset[/tex] S} for
X0 = (1,2,-1,3); S = open 4-ball of radius 7 about (0,3,-2,2).


Homework Equations



If X1 is in Sr(X0) and
|X - X1| < [tex]\epsilon[/tex] = r - |X - X0|
then X is in Sr(X0)

The Attempt at a Solution



This is my first foray into n-dimensional analysis and I'm pretty intimidated. :bugeye: I understand the theory behind it I think--we're making a little n-dimensional ball around the point X0, and in fact trying to maximize the size of the ball while still remaining in the bigger ball our set is defined by.

I'm confused about the actual determination of the size of [tex]\epsilon[/tex] though. What do I use for this arbitrary point X in the equation?

This is a multi-part problem and I could do the ones in dimensions I could visualize. :P Can anyone help me out with this 4D stuff? Thanks.

Edit: the answer in the back of the book says the supremum is 5.
 

Answers and Replies

  • #2
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You have a ball of radius 7 around the point (0, 3, -2, 2).

How big a ball can you have around (1, 2, -1, 3) so that it fits inside the ball of radius 7?

A sketch of the situation in 2D will be helpful, even despite the fact that you're dealing with a four-dimension space.
 

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