Finding the Tangent Line at y = x * e^(2x) | (2, 2*e^(4)) - Homework Solution

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Homework Help Overview

The discussion revolves around finding the equation of the tangent line to the curve defined by y = x * e^(2x) at the specific point (2, 2*e^(4)). Participants are exploring the differentiation of the function and the application of the point-slope form of a line.

Discussion Character

  • Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the derivative of the function and its evaluation at the point of interest to determine the slope of the tangent line. There are questions about the correctness of the derived equation and whether the process seems overly simplistic.

Discussion Status

Some participants express uncertainty about the correctness of their solutions, while others affirm that the steps taken appear valid. There is a general acknowledgment of the process involved in finding the tangent line, but no explicit consensus on the final answer.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may influence their approach and the level of detail they provide in their reasoning.

Justabeginner
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Homework Statement


Find the equation of the tangent line at the curve y= x * e^(2x) at the point (2, 2*e^(4))


Homework Equations





The Attempt at a Solution


f'(x)= e^(2x) * (2x+ 1)
(e^4)(5) = 5e^4
y- 2*e^4 = 5*e^4 (x-2)
y= 5(e^4)*x - 8*(e^4)

Is this right? It seems too easy for me to have gotten it right :/ Thanks.
 
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Justabeginner said:

Homework Statement


Find the equation of the tangent line at the curve y= x * e^(2x) at the point (2, 2*e^(4))


Homework Equations





The Attempt at a Solution


f'(x)= e^(2x) * (2x+ 1)
(e^4)(5) = 5e^4
To clarify, the above should be
f'(2) = (e^4)(5) = 5e^4
You're finding the slope of the tangent line when x = 2.
Justabeginner said:
y- 2*e^4 = 5*e^4 (x-2)
y= 5(e^4)*x - 8*(e^4)

Is this right? It seems too easy for me to have gotten it right :/ Thanks.

Looks OK.
If you understand the steps involved (find the slope of the tangent, use the point-slope form of the line), it's not very hard.
 
Yes sir, that is what I got! Thank you very much.
 

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