Finding the Temperature at which Oxygen Molecules Have Double the RMS Speed

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SUMMARY

The discussion focuses on determining the temperature at which oxygen molecules have a root mean square (RMS) speed that is double their speed at 0 degrees Celsius. The equation used is 1/2mv² = 3/2kT, where temperature must be converted to Kelvin for accurate calculations. The participants clarify that 0 degrees Celsius is equivalent to 273.15 Kelvin, and they emphasize the importance of using the correct temperature scale in thermodynamic equations.

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  • Understanding of the kinetic theory of gases
  • Familiarity with the RMS speed formula
  • Knowledge of temperature conversion from Celsius to Kelvin
  • Basic grasp of thermodynamic principles
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  • Learn about the implications of temperature on molecular speed
  • Explore the relationship between kinetic energy and temperature in gases
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Ry122
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Problem:
At what temperature do oxygen molecules have an rms speed that is double their speed at 0 degrees?
Using 1/2mv^2 = 3/2KT I am unable to solve for v since T is 0. Is there another way to do this?
 
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Are you sure it doesn't mean 0 degrees celsius? In that formula, temperature is measured in Kelvin.
 
Last edited:
i had to convert 0 degrees to kelvin
thanks
 

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