A m1 = 7.3 kg block and a m2 = 10.2 kg block, connected by a rope that passes over a frictionless peg, slide on frictionless incline.
(a) Find the acceleration of the blocks and the tension in the rope.
(b) The two blocks are replaced by two others of masses m1 and m2 such that there is no acceleration. Find whatever information you can about the masses of these two new blocks.
m1/m2 = ?
T = (m1g)(1 + (((m2sin(50 deg)) - (m1sin(40 deg)))/(m1 + m2))
The Attempt at a Solution
(a) in order to find the acceleration of the blocks I used the acceleration equation above to get...
http://www5a.wolframalpha.com/Calculate/MSP/MSP97820d5a6g74c9g0833000042fai256cg284eae?MSPStoreType=image/gif&s=54&w=353.&h=43. [Broken] = 1.75 m/s2
But I am having trouble finding the tension. Using the equation above I do not get the right answer.
http://www4c.wolframalpha.com/Calculate/MSP/MSP110351gc6963gg3d1i776000051bdi059eic3399d?MSPStoreType=image/gif&s=3&w=322.&h=37. [Broken] = 84.39 N
Is this the right equation? What do I need to do differently?
(b) I really have no idea what this part is asking for. If a = 0 wouldn't m1 and m2 both be equal to 0?
Last edited by a moderator: