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## Homework Statement

A

*m*1 = 7.3 kg block and a

*m*2 = 10.2 kg block, connected by a rope that passes over a frictionless peg, slide on frictionless incline.

(a) Find the acceleration of the blocks and the tension in the rope.

(b) The two blocks are replaced by two others of masses

*m*1 and

*m*2 such that there is no acceleration. Find whatever information you can about the masses of these two new blocks.

m

_{1}/m

_{2}= ?

## Homework Equations

(a)

http://www5a.wolframalpha.com/Calculate/MSP/MSP15211ddd67249f6c0h99000021236a56865d5b05?MSPStoreType=image/gif&s=30&w=226.&h=36. [Broken]

T = (m1g)(1 + (((m2sin(50 deg)) - (m1sin(40 deg)))/(m1 + m2))

## The Attempt at a Solution

(a) in order to find the acceleration of the blocks I used the acceleration equation above to get...

http://www5a.wolframalpha.com/Calculate/MSP/MSP97820d5a6g74c9g0833000042fai256cg284eae?MSPStoreType=image/gif&s=54&w=353.&h=43. [Broken] = 1.75 m/s

^{2}

But I am having trouble finding the tension. Using the equation above I do not get the right answer.

http://www4c.wolframalpha.com/Calculate/MSP/MSP110351gc6963gg3d1i776000051bdi059eic3399d?MSPStoreType=image/gif&s=3&w=322.&h=37. [Broken] = 84.39 N

Is this the right equation? What do I need to do differently?

(b) I really have no idea what this part is asking for. If a = 0 wouldn't m

_{1}and m

_{2}both be equal to 0?

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