Finding the third derivative of f(x) = 1/x² + 4x + 9 + x⁴

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s883
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Homework Statement


Could anyone explain me how to solve this?

Homework Equations



f(x) =
1/x2 + 4x + 9 + x4 , f’”’(-2) =


The Attempt at a Solution

 
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Hello s883! :smile: It means to take the 4th derivative of the given function f(x) and then evaluate the resulting expression at x = -2. And I would probably put calculus questions in the calculus forum for next time :wink:
 
I assume you mean [itex]f(x) = 1/x^2 + 4x + 9 + x^4= x^{-2}+ 4x+ 9+ x^4[/itex].

Can you find f'(x) using the "power rule" ([itex](x^n)'= n x^{n-1}[/itex])?

What about f'' and f'''?

Now do f''''.