Finding the total resistance of a complex combination

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Homework Help Overview

The discussion revolves around finding the total resistance of a complex combination of resistors, involving various configurations and the application of circuit analysis techniques.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of Kirchhoff's rules and express confusion regarding their application in the given resistor configuration. Some suggest labeling currents and applying Kirchhoff's Voltage Law (KVL) and Kirchhoff's Current Law (KCL) to analyze the circuit. Others mention the potential use of a triangle-star transform to simplify the circuit.

Discussion Status

There is ongoing exploration of different methods to approach the problem, with participants seeking clarification on how to apply suggested techniques effectively. Some guidance has been offered regarding labeling currents and using circuit analysis principles, but participants express a need for further elaboration on these methods.

Contextual Notes

Participants note confusion about the unusual configuration of the resistors and the appropriate application of circuit laws. There is mention of specific values and assumptions regarding current and voltage sources, but no consensus has been reached on the best approach to solve the problem.

hms.tech
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b]1. Homework Statement [/b]

Find the total resistance of this complex combination of resistors.
Final.jpg
[

Homework Equations



R(total)= (Rr)/(R+r)

The Attempt at a Solution



resistance of r(2) and r(3) = 20Ω
resistance of the combination of r(1) and the resultant 20 Ω(ie r(2) and r(3) ) = 20/3
resistance of r(3) and r(5) = 20Ω
resistance of te combination of r(4) and the resultant 20 (ie r(3) and r(5) ) = 20/3

I can't deduce and answer from the above (correct) results.

Need urgent Help !
 
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hi hms.tech! :smile:

have you tried using Kirchhoff's rules?
 
tiny-tim said:
hi hms.tech! :smile:

have you tried using Kirchhoff's rules?

No!
Would you kindly guide me how and where do we apply them in this situation.

(i know what they are but am confused about their appropriate application in this design of resistors)
 
hi hms.tech! :wink:
hms.tech said:
No!
Would you kindly guide me how and where do we apply them in this situation.

(i know what they are but am confused about their appropriate application in this design of resistors)

just label the currents I1 I2 I3 I4 and I6 (with arrows of course!), do KVL and KCL, then find the total voltage drop between A and B, and divide by I6

what do you get? :smile:
 
as i said, i am confused about the way to apply these laws in this unusual situatuion
your 2nd answer did not help any more than the first one (@tiny tim).

Kind Sir, will elaborate on the proposed method.
to put it simply, i am unable to find the voltage drop between A and B.
 
hms.tech said:
as i said, i am confused about the way to apply these laws in this unusual situatuion
your 2nd answer did not help any more than the first one (@tiny tim).

Kind Sir, will elaborate on the proposed method.
to put it simply, i am unable to find the voltage drop between A and B.

Stick either a voltage source or a current source at terminals AB. If it's a current source, find the voltage drop across AB. If it's a voltage source, find the current it's driving into the circuit. Either way the overall resistance of the circuit will be the ratio of the voltage to the current that the source delivers.
 
http://en.wikipedia.org/wiki/Y-Δ_transform
This is how you gona solve it.
1,2 and 3 are in triangle, same 3,4,5, change one combination with triangle-star transform and its solved.
My result is 10 ohm.
With kirchhoff.
Lets make I6=10 (you can give it any value you want)
Now, when the current is at A it will be divided by 2, because R1=R2, I3=0 from KCL.
So I1=5, I2=5, i4=5, i5=5.
Now, what you gona do its to KVL in loop 1 (yellow) to find Uab.
After finding Uab, Rab=Uab/I6.
https://www.physicsforums.com/attachment.php?attachmentid=45015&stc=1&d=1331595516
 

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This circuit can be analyzed by the use of symmetry.

An equivalent circuit to this is on with A at one corner of a square, and B at the opposite corner.

Label the other two corners C & D respectively, the corners being labeled: A, C, B, and D in a clockwise sense.
Resistor 1 connects corners A and C.

Resistor 2 connects corners A and D.

Resistor 5 connects corners C and B.

Resistor 4 connects corners D and B.

Resistor 3 connects corners D and C.​
 

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