Finding the volume of a solid.

  • Thread starter Thread starter tarmon.gaidon
  • Start date Start date
  • Tags Tags
    Solid Volume
Click For Summary

Homework Help Overview

The problem involves finding the volume of a solid in the first octant, defined by the coordinate planes and the planes described by the equations 2x+y-4=0 and 8x-4z=0. This is situated within a calculus context, specifically focusing on integration bounds and coordinate transformations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the difficulty of determining the appropriate bounds for integration and the challenges associated with changing the order of integration and coordinate systems. Some suggest visualizing the solid through sketches to aid in understanding the region of integration.

Discussion Status

There is an ongoing exploration of different approaches to the problem, with some participants providing suggestions for visual aids and questioning the assumptions made about integration limits. No explicit consensus has been reached regarding the best method to approach the problem.

Contextual Notes

Participants express concerns about the complexity of switching between cylindrical and Cartesian coordinates, indicating that the problem may involve multiple interpretations of the solid's boundaries and integration limits.

tarmon.gaidon
Messages
30
Reaction score
0

Homework Statement


Find the volume of the solid in the first octant bounded by the coordinate planes and the plane 2x+y-4=0 and 8x-4z=0.


This is a problem for a practice exam for my calculus course and I just need some help getting started.

I have had a lot of trouble in this course trying to figure what the bounds of my integration should be so any pointers would be appreciated!

P.S. I have also had a lot of trouble reversing the oder of integration and changing to spherical and cylindrical coordinates. Mainly because I have trouble figuring out how to change the bounds.
 
Last edited:
Physics news on Phys.org
tarmon.gaidon said:

Homework Statement


Find the volume of the solid in the first octant bounded by the coordinate planes and the plane 2x+y-4=0 and 8x-4z=0.


This is a problem for a practice exam for my calculus course and I just need some help getting started.

I have had a lot of trouble in this course trying to figure what the bounds of my integration should be so any pointers would be appreciated!
This is not surprising, since for many problems of this kind, finding the bounds of integration is the hardest part.

Have you drawn a picture of the solid? Drawing a picture should give you a good idea of what the region of integration looks like, and should help you get the limits of integration.
tarmon.gaidon said:
P.S. I have also had a lot of trouble reversing the oder of integration and changing to spherical and cylindrical coordinates. Mainly because I have trouble figuring out how to change the bounds.
 
i wouldn't be using spherical or cylindrical, but would have a think about the volume - and try and draw it... what's you attempts at you bounds?
 
Hey Mark,

Thanks for the suggestion, I see what you are saying but let me ask this.

I have a problem here where I needed to change a triple integral from cylindrical coordinates to Cartesian. I have attached an image of the problem and the solution. When I went to solve it I sketched the solid and then attempted to write the bounds of each variable. I had come to the conclusion that y should be from \sqrt{1-x^2} to 1 which is close but not quite right. How would I come to the conclusion they made instead of what I did?
 

Attachments

  • untitled.PNG
    untitled.PNG
    15.4 KB · Views: 532
Wow, that image would not help me learn ANYTHING!
The limits for "r" and theta will help you determine the limits for x and y.
Since theta only ranges from 0 to π and r ranges from 0 to 1, it is a SEMIcircle of radius one (the top half, actually). To integrate the top of the unit circle "dydx"...

The upper limit for a vertical representative rectangle will range from y = 0 (the x-axis) to the curve y = +√(1-x^2). (...I included the "+" to emphasize that it's the top half).

Then x ranges from -1 to 1.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
5K
Replies
3
Views
2K
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K