Volume of solid by using projection to different planes

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Homework Help Overview

The discussion revolves around finding the volume of a solid bounded by the equation z = 4 - x - y, with specific constraints on the x and y variables. Participants are exploring the differences in results obtained from using different projections (zx-plane and xy-plane) for the volume calculation.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are comparing results from different projection methods, questioning where discrepancies arise in their calculations. Some express confusion regarding the correct setup of integrals for the zx-plane projection.

Discussion Status

There is an ongoing exploration of the correct limits and setup for the integrals needed to calculate the volume. Some participants have provided guidance on visualizing the projection, while others are seeking clarification on their diagrams and integral limits.

Contextual Notes

Participants are working under the constraints of the problem statement, specifically the defined bounds for x and y, and are discussing the implications of these constraints on their volume calculations.

chetzread
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Homework Statement


Find the volume of solid which is bounded by z = 4-x-y and below by region in the plane of 0<x<2 , 0<y<1
When i use zx -plane projection , i found that my ans is different with the ans of using xy projection ...Which part i did wrongly ?

From the ans given , volume = 5 unit , when i use xy plane projection , i gt this ans , but when I use zx -plane projection , i got V = 6

For zx -plane projection , i got V = ∫∫∫ dydxdz , 0<x <2 , 0 <z< 4-x , 0<y<1

Homework Equations

The Attempt at a Solution

 

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chetzread said:

Homework Statement


Find the volume of solid which is bounded by z = 4-x-y and below by region in the plane of 0<x<2 , 0<y<1
When i use zx -plane projection , i found that my ans is different with the ans of using xy projection ...Which part i did wrongly ?

From the ans given , volume = 5 unit , when i use xy plane projection , i gt this ans , but when I use zx -plane projection , i got V = 6

For zx -plane projection , i got V = ∫∫∫ dydxdz , 0<x <2 , 0 <z< 4-x , 0<y<1

Homework Equations

The Attempt at a Solution

Your zx plane projection is incorrect. You need two integrals because when you integrate in the y direction first, sometimes you hit the plane ##y=1## and sometimes you hit the plane ##z = 4-x-y##. In fact if you do the order dydxdz instead of dydzdx you may need 3 integrals.
 
LCKurtz said:
Your zx plane projection is incorrect. You need two integrals because when you integrate in the y direction first, sometimes you hit the plane ##y=1## and sometimes you hit the plane ##z = 4-x-y##. In fact if you do the order dydxdz instead of dydzdx you may need 3 integrals.
sorry , i still didnt get you , how should the whole integral look like ? What is the limit fro x , y and z ?
 
chetzread said:
sorry , i still didnt get you , how should the whole integral look like ? What is the limit fro x , y and z ?

I'm not going to work it for you. What you need to do is imagine you are looking at the zx plane from straight down the y axis. Take your picture and project every line onto the zx plane. That will show you the shape of the zx region, which is what you need to find the limits.
 
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LCKurtz said:
I'm not going to work it for you. What you need to do is imagine you are looking at the zx plane from straight down the y axis. Take your picture and project every line onto the zx plane. That will show you the shape of the zx region, which is what you need to find the limits.
is my diagram wrong ?
 
here's my zx plane . with 0<x <2 , 0 <z< 4-x , is it correct ?
 

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Here's a correct picture:

volume.jpg


You need to draw the projection of ##a## and ##b## and the line between them on the zx plane. The point ##a## is incorrectly drawn in your original sketch
 
Last edited:

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