Finding the zeroes for cubic equation

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Homework Help Overview

The discussion revolves around finding the zeroes of the cubic function f(x) = x^3 + 25x. Participants are exploring the methods of factoring and verifying potential solutions.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to factor the cubic equation and identifies potential zeroes as 0, -5i, and +5i. Some participants question the validity of these solutions, suggesting the need for verification through substitution.

Discussion Status

Participants are actively verifying the proposed solutions by substituting them back into the original function. There is acknowledgment of a discrepancy between the calculated solutions and an external solution provided, leading to further questioning of the latter's accuracy.

Contextual Notes

There is an indication of frustration regarding the correctness of the solutions, and participants are encouraged to check the solutions they were given for additional clarity.

dmoney123
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Homework Statement



Find all zeroes for the function f(x)

f(x)=x^3+25x

Homework Equations


The Attempt at a Solution



I tried factoring out x out of it.

x(x^2+25)

and again to give

x[(x+5i)(x-5i)]

this would give me the 0,-5i,+5i as the zeroes. Doesn't seem to be right though.

Any thoughts?

Thanks!
 
Last edited:
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dmoney123 said:

Homework Statement



Find all zeroes for the function f(x)

f(x)=x^3+25x


Homework Equations





The Attempt at a Solution



I tried factoring out x out of it.

x(x^2+25)

and again to give

x[(x+5i)(x-5i)]

this would give me the 0,-5i,+5i has the zeroes. Doesn't seem to be right though.

Any thoughts?

Thanks!

Try substituting in your three solutions, to see if they work. You should always check your solutions this way, and you can certainly do it as easily as we can.
 
(5i)^3+25(5i)=
-125i+125i=0

(-5i)^3+25(-5i)=
125i-125i=0

0^3+25(0)=0

seems to check out for me. however this is not giving me the correct answer according to the solution
 
dmoney123 said:
(5i)^3+25(5i)=
-125i+125i=0

(-5i)^3+25(-5i)=
125i-125i=0

0^3+25(0)=0

seems to check out for me. however this is not giving me the correct answer according to the solution

Your solution is correct, so that must mean that the solution you were given is wrong.
 
Thanks for your help. Sure is frustrating when you start doubting yourself. Take care.
 
You could also have checked the incorrect solutions you were given for peace of mind.
 

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