Finding theta of a charged pendulum

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Homework Help Overview

The discussion revolves around a physics problem involving a charged pendulum. A small spherical insulator with a positive charge is suspended by a wire, while a negative charge is positioned nearby, creating an angle θ with the vertical due to the electrostatic force acting on the insulator.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants explore the calculation of the electrostatic force and its relation to the motion of the pendulum. There are discussions about using trigonometric functions to find the angle θ, with some questioning the appropriateness of using inverse cosine for a force value. Others suggest drawing a free body diagram to clarify the forces at play.

Discussion Status

The discussion has progressed with participants offering guidance on using free body diagrams and vector algebra to approach the problem. There is recognition of the need to clarify the relationships between the forces acting on the pendulum and the angle θ, although no explicit consensus has been reached.

Contextual Notes

Participants note potential confusion regarding the calculation of the electric force and the proper use of trigonometric functions in the context of the problem. There is an acknowledgment of the complexity of the situation and the importance of accurately representing the forces involved.

whitejac
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Homework Statement


a small spherical insulator of mass 6.00×10−2 kg and charge +0.400 μC is hung by a thin wire of negligible mass. A charge of −0.220 μC is held 0.290 m away from the sphere and directly to the right of it, so the wire makes an angle theta with the vertical. What is the angle θ (k=1/4πϵ0=8.99×109 N · m2/C2)

Homework Equations


F = k q1q2/d^2

The Attempt at a Solution


So I can find the force acting on the mass. That's easy:
Plugging in I get (8.99x10^9)(0.4x10^-12)(-2.2x10^-12) / (0.29 * 0.29)
Which equals: (-7.9112 x 10^-15) / 0.0841
Which equals: (-9.41 x 10^-14)N

I cannot, however, figure out how to correlate this force to an act of motion. I could see it pulling laterally (the y component being negligable?) but how it could do them both with this stage of math because the string should theoretically be fixed in length and thus pull as an arc instea of a straight line, however I believe they are asking for a straight line.
 
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**Edit, I mistook the prefixes. It should be 10^-6, not 10^-12. The resulting force should be -0.941N, much larger.
 
I think the system looks like the figure below. The pendulum charge sits at rest at angle θ with the other point charge located horizontally to the right.
 

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  • Pend charge.png
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Yes, i believe it does look like that.
So then, I could find theta by using inverse cosine on the resulting force, which would give me the angle to the lower right of that triangle, and 90-ans would give me theta?
 
whitejac said:
Yes, i believe it does look like that.
So then, I could find theta by using inverse cosine on the resulting force, which would give me the angle to the lower right of that triangle, ...
I'm not sure. Can you show in more detail what you mean here?
 
I guess what I mean is:
Theta = 90 - arcos(-0.941)?
The force pulls it away along the x axis, so to the left of the pendulum would create an angle of arccos(-0.941) and with the triangle being a right triangle then the only thing we'd need to conclude the theta would be to subtract that answer from 90 degrees.
 
I don't get 0.941 N for the electric force if I use 0.400 μC and 0.220 μC. It appears to me that your decimal point is in the wrong place in your answer.

More important, what is the justification for taking the inverse cosine of the force? Whenever you take the inverse cosine of a number, the number should be dimensionless.

I recommend that you draw a free body diagram for the pendulum charge and use what you know about the sum of the forces acting on an object that remains at rest.
 
I cannot recall what my justification for using inverse cosine was, but I simply must thank you for your assistance. I was looking at this problem as more complicated than it had to be. When I did the force body diagram like you said, I saw what the situation really was. the string was an equal and opposite Fx Fy force. Theta is equal to inverse tangent of Fy/Fx. So I was able to solve this problem once I reviewed my vector algebra and got the trigonometry worked out.
 
OK. Good work!
 

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