Finding Thevenin Voltage in a Complex Circuit

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Homework Help Overview

The discussion revolves around finding the Thevenin voltage in a complex circuit involving resistors in series and parallel configurations. The original poster attempts to understand the current division in the circuit, particularly regarding the behavior of the 10 and 20 ohm resistors.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the total resistance of branches and question the reasoning behind ignoring terminals A and B. There is an exploration of how current divides between equal resistances in parallel.

Discussion Status

The discussion is active, with participants clarifying concepts related to current flow and resistance. Some guidance has been provided regarding the behavior of current in the circuit, particularly in relation to open terminals.

Contextual Notes

There is an assumption that terminals A and B do not affect current flow as they are open, which is a point of clarification in the discussion.

sugz
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Homework Statement


The question is in the photo attached.

Homework Equations

The Attempt at a Solution


I have found the Thevenin voltage as the 10 and 20 ohm resistors are in series (30 ohms) and the 50 and 40 ohm resistor are in series (90ohms). The 30 and 90 ohm resistors are in parallel so

30||90 = (30×90)/(30+90) =22.5 ohms

I am having struggles with determine the Thevenin voltage as the solution says the 8 A current gets divided equally among the 10 and 20 ohm resistor but I don't understand why.
 

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What is the total resistance of each branch (ignore the terminals A and B for the moment)?
 
60 ohms but how can we ignore terminals a and b?
 
sugz said:
60 ohms but how can we ignore terminals a and b?
I said ignore them for the moment. You can do this because they are open: not connected to anything so they do not pass any current.

So both of these branches have the same resistance, correct? The branches are in parallel, correct? How will current divide between equal resistances in parallel?
 
So since current doesn't pass through terminal a and b, they just flow down to the next resistor?
 
sugz said:
So since current doesn't pass through terminal a and b, they just flow down to the next resistor?
Yes. They are the only available paths.
 
Okay, that makes sense then, thank you!
 

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