Finding unit normal vectors and normal/tangent components of accelerat

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SUMMARY

The discussion focuses on finding the unit tangent vector T(t), unit normal vector N(t), and the tangential and normal components of acceleration (aT and aN) for the vector function r(t) = at t = 1. The relevant equations used include T(t) = r'/||r'||, N(t) = T'/||T'||, aT = a . T = (v . a)/||T||, and aN = a . N = ||v x a||/||v|| = sqrt(||a||² - aT². Participants clarify the differentiation process and the simplification of the unit tangent vector, ensuring accuracy in calculations.

PREREQUISITES
  • Understanding of vector calculus, specifically differentiation of vector functions.
  • Familiarity with the concepts of unit tangent and normal vectors.
  • Knowledge of acceleration components in vector form.
  • Proficiency in using the quotient rule for differentiation.
NEXT STEPS
  • Learn how to apply the quotient rule in vector calculus for differentiating vector functions.
  • Study the geometric interpretation of unit tangent and normal vectors in three-dimensional space.
  • Explore the relationship between acceleration components and curvature in vector functions.
  • Practice problems involving the calculation of normal and tangential components of acceleration for various vector functions.
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Students studying vector calculus, particularly those focusing on motion in three dimensions, as well as educators seeking to clarify concepts related to unit vectors and acceleration components.

icesalmon
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Homework Statement


given r(t) = <t, 1/t,0> find T(t) N(t) aT and aN at t = 1


Homework Equations


T(t) = r'/||r'||
N(t) = T'/||T'||
aT = a . T = (v . a)/||T||
aN = a . N = ||v x a||/||v|| = sqrt(||a||2 - aT2)


The Attempt at a Solution


for my T(t) I get <t2, -1 , 0>/(sqrt(1+t4) (I like keeping things in 3 dimensions even if there is no contribution in the z direction)
and I am not calculating the normal vector if there isn't some algebra I can use to simplify this greatly , which I am not seeing, t4 + 1 I don't believe I can factor and I can't think of any other way to simplify this one so I'm just moving around through the problem set looking for some r(t) = <cost, sint, t> type of vector that I can simply differentiate and use identities with, desperately trying to avoid those other problems
 
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icesalmon said:

Homework Statement


given r(t) = <t, 1/t,0> find T(t) N(t) aT and aN at t = 1


Homework Equations


T(t) = r'/||r'||
N(t) = T'/||T'||
aT = a . T = (v . a)/||T||
aN = a . N = ||v x a||/||v|| = sqrt(||a||2 - aT2)


The Attempt at a Solution


for my T(t) I get <t2, -1 , 0>/(sqrt(1+t4)
How did you get that? Your first equation in the "relevant equations" section is ##T(t) = r' / \|r\|##. What is ##r'## in this case?
 
r' = <1,-1/t2>
|r'| = sqrt(1 + 1/t4)
did I mess something up when differentiating/doing algebra/both?
 
|r'| = sqrt((t4+1)/t4) = (1/t2)sqrt(t4+1)
which should be t2r'/(|r'|)
which I believe is actually <t2,-1>/(sqrt(t4+1)
which is the same thing...oops I'm not sure what I'm messing up here.
 
icesalmon said:
|r'| = sqrt((t4+1)/t4) = (1/t2)sqrt(t4+1)
which should be t2r'/(|r'|)
which I believe is actually <t2,-1>/(sqrt(t4+1)
which is the same thing...oops I'm not sure what I'm messing up here.
OK, that looks fine. So what is ##T'##? Just use the quotient rule, it shouldn't be too horrible.
 
well that's what I'm saying, are there any ways I can simplify this particular unit tangent vector before differentiating? I know how to differentiate it, but on an exam I will chew up a ton of time making sure I keep everything straight with the differentiation in terms of signs and cancellations.
 

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