Finding Vector v Given a, b, and c

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Homework Help Overview

The problem involves finding an unknown vector v that satisfies two equations involving known vectors a, b, and c: the dot product b . v = a and the cross product b x v = c. The context is vector analysis, specifically focusing on vector operations and relationships.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss starting points involving dot and cross products, with one expressing uncertainty about how to manipulate the equations effectively. There are mentions of using trigonometric relationships related to the angles between vectors.

Discussion Status

Some participants have offered guidance on exploring the relationships between the magnitudes and directions of the vectors involved. There is an acknowledgment of the complexity of the problem, with participants expressing their struggles and seeking further clarification.

Contextual Notes

There is a noted confusion regarding the interpretation of the magnitudes involved, particularly with the notation used for vector c. The discussion reflects the challenges of working with multiple vector equations simultaneously.

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Homework Statement



The unknown vector v satisfies b . v = a and b x v = c, where a, b, and c are fixed and known. Find v in terms of a, b, and c.

Homework Equations





The Attempt at a Solution

 
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And what have you tried? Personally, I would start with finding the dot and cross products there...
 
I understand dot and cross product. I've played with it a lot, mostly with cross product, but I'm not getting anywhere. I have a feeling that I'm suppose to manipulate it using some other trick. Can someone guide me in the right way?
 
Have you tried

b \cdot v = |b||v|cos \theta
| b \times v | = |b||v|sin \theta
 
(|b||v|)^2 = a^2 + c^2
v . v = |v|^2 = (a^2 + c^2) / |b|^2

And I'm stuck...
 
duoshikunli said:
(|b||v|)^2 = a^2 + c^2
v . v = |v|^2 = (a^2 + c^2) / |b|^2

And I'm stuck...
Check your work c^2 means nothing.
I assume you mean |c|^2.

A vector is uniquely determined by it's magnitude and direction.

You have |v| all you need now is a unit vector in v's direction.
 

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