Finding velocity components of point in the middle of a tricycle

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Homework Help Overview

The discussion revolves around calculating the velocity components of a point (P) located between the front wheel and the center of the rear wheels of a tricycle. The problem involves understanding the relationship between the angular velocity, the velocity of the front wheel, and the geometry of the tricycle's movement.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the calculation of angular velocity and its influence on the velocity of point P. There are attempts to clarify the local coordinate system and how it relates to the movement of point P. Questions arise regarding the influence of the front wheel angle on the velocity components.

Discussion Status

Participants are actively discussing the geometry involved in determining the center of rotation and how to derive the velocities from the given parameters. Some guidance has been offered regarding the relationships between the angular velocity, radius, and direction of movement, but no consensus has been reached on the final calculations.

Contextual Notes

There are indications of confusion regarding the local coordinate system and the assumptions about the movement of point P in relation to the tricycle's turning dynamics. The discussion also reflects on the need for clarity in defining the parameters and their relationships.

Krus
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Homework Statement


I have a tricycle with a following data (see attachment):
  • Distance (d) between center of front wheel (F) and center between rear wheels (C) = 325 mm
  • Velocity of front wheel (VF) = 50 mm/s
  • Angle of front wheel (α) = changing between -90;90
  • Distance between point C and P = 129 mm
Out of this data, I calculated the angular velocity by using the following formula:
ω = (sin(α) * vF) / d

What I need, is the component velocity of a point between the front wheel and the center between rear wheels (P) in its local coordinate system. This local coordinate system is for sure turning with the vehicle.

Homework Equations



The Attempt at a Solution


To calculate the velocity in point P i used the angular velocity and the distance between C and P:

vP = ω * 129 mm

This is for sure right, if α = ±90. But If α = 0, my vP is also 0, which can't be.
So somehow the velocity connected with the front wheel angle α must have an influence as well.

Finally, I need to split the velocity of point P into its X- and Y-component.

Thanks for your help.
Krus
 

Attachments

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    Untitled.png
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Hello Krus, and welcome to PF.

Your problem statement
What I need, is the component velocity of a point between the front wheel and the center between rear wheels (P) in its local coordinate system. This local coordinate system is for sure turning with the vehicle.
surprises me. In the local coordinate system of the vehicle, P isn't moving at all. :)
 
Hi :)

OK, I'm sorry.. The description was maybe a bit wrong.
I try to explain what I need in some examples:

If vF = 50 mm/s and α = 0, then the y-component of the velocity would also be 50 mm/s, x-component and ω is then 0.

If vF = 50 mm/s and α = 90, then the vehicle is turning around its point C -> x-component and ω can't be 0 in point P.

If vF = 50 mm/s and α = 45, then the vehicle drives in a circle around a center point, which is outside of the vehicle. Then there is a smaller ω than when α = 90, but I have a higher y-component velocity.

I mean in point C, can only exist a y-velocity and an angular velocity. It can't happen that there is a velocity in x-direction. But in point P it is different, because it's not the turning centre.

So there must be a formula, how to calculate the speed in components (x-,y- and angular) for point P.

Sorry, It's kind of difficult to describe the problem :(
 
I suggest figuring out from the geometry where the centre of rotation is. P then describes an arc about that point.
Krus said:
the component velocity of a point between the front wheel and the center between rear wheels (P) in its local coordinate system.
I guess you mean the co-ordinate system fixed on the ground at the point where P happens to be at this instant, with the y-axis along CP.
 
haruspex said:
I guess you mean the co-ordinate system fixed on the ground at the point where P happens to be at this instant, with the y-axis along CP
Yes, you're right, that's what I mean.:)

Do you have any Idea how to get these velocities?
For sure I can get the center of rotation out of the geometry, but how to use these data to get the velocities?

Thanks
 
Krus said:
For sure I can get the center of rotation out of the geometry, but how to use these data to get the velocities?
Can you figure out the angular velocity?
If you draw a radius from P to the centre of rotation, how long is that radius and what is the direction of movement of P in relation to that?
 
Yes...

The angular velocity and all other values (see image) are the following:

ω = (VF * sin(α)) / d
r = d / tan(α)

length of radius:
q
= √(r2 + CP2)

direction of movement of P:
β
= atan(CP / r)
 

Attachments

  • Untitled_1.png
    Untitled_1.png
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Krus said:
Yes...

The angular velocity and all other values (see image) are the following:

ω = (VF * sin(α)) / d
r = d / tan(α)

length of radius:
q
= √(r2 + CP2)

direction of movement of P:
β
= atan(CP / r)
Yes to all those. I was rather hoping you'd see how to finish it from there.
What is the speed in the direction of movement? What are the x and y components of that?
 
Well, i guess the following:

Speed of movement in P:
vP = q * ω

Components:
vPX = VP * sin(β)
vPY = VP * cos(β)

Right? ;)
 
  • #10
Krus said:
Well, i guess the following:

Speed of movement in P:
vP = q * ω

Components:
vPX = VP * sin(β)
vPY = VP * cos(β)

Right? ;)
Yes, that all looks right.
 

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