Finding Velocity of a Dropped Shellfish

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SUMMARY

The problem involves calculating the total velocity of a shellfish dropped from a height of 30 meters by a sea hawk flying at 15 m/s. The vertical velocity upon impact is calculated using the equation vf² = vi² + 2ah, resulting in a vertical velocity of 24.3 m/s. To find the total velocity, the horizontal velocity of 15 m/s is combined with the vertical velocity using the Pythagorean theorem, yielding a total impact velocity of 28.5 m/s. Air resistance is neglected in this scenario.

PREREQUISITES
  • Understanding of kinematic equations, specifically vf² = vi² + 2ah
  • Knowledge of vector addition for combining horizontal and vertical velocities
  • Familiarity with the concept of conservation of energy in physics
  • Basic understanding of projectile motion
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  • Study the Pythagorean theorem for calculating resultant velocities
  • Learn about projectile motion and its equations
  • Explore conservation of energy principles in physics
  • Review the effects of air resistance on falling objects
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Students in physics courses, educators teaching kinematics, and anyone interested in understanding the principles of motion and velocity calculations.

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Homework Statement


5. A sea hawk flying horizontally at a speed of 15 m/s drops a shellfish from a height of 30 m. At what speed does the shellfish hit the ground? Neglect air resistance (drag).



Homework Equations



vf2 = vi2 + 2ah

The Attempt at a Solution



I got 24.3 which was one of the answers and when i emailed the professor he said that that was the vertical velocity and I need to look for total velocity...well the answer is 28.5 m/s and I don't understand how that was arrived.
 
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You could use conservation of energy here I believe.


Also, the horizontal velocity would be the same throughout.
 

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