The discussion centers on calculating the phasor voltage given a current phasor of I=75<120° and a resistance of R=4kΩ. The correct approach is to multiply the current's magnitude by the resistance while keeping the angle unchanged. Thus, the resulting phasor voltage is V=300000<120°, confirming that only the magnitude is affected by the multiplication with the real constant.
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pokie_panda said:Homework Statement
I=75<120 deg.
R= 4k
find phasor voltage
does the 4,000 multiply the 75 only so you get
300000<120
or does it multiply 4,000 both values including the angle ?