Finding Volume of Solid Using Disc/Washer Method for Rotation about the Y-Axis

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SUMMARY

The discussion focuses on calculating the volume of a solid formed by rotating the function f(x) = 4x - x² and the line y = 4 about the y-axis using the disc/washer method. The user initially solved the problem using the shell method, obtaining a volume of 128/3 π. The correct approach involves splitting the volume calculation into two parts: from x = 0 to x = 2 using the disc method and from x = 2 to x = 4 using the washer method. The integration limits must be expressed in terms of y due to the orientation of the discs/washers being vertical.

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Homework Statement



I need to find the volume of the solid formed when rotating f(x) = 4x-x^2 and y=4 and x=0 about the y-axis.

Using the disc/washer method.

Homework Equations



v = pi * integral from a to b of (r^2) * thickness

The Attempt at a Solution



I already did it using the shell method and got 128/3 pi.

I am getting confused on how to do this, I believe it will need to be setup in 2 parts? Refer to my image sketch:

[PLAIN]http://k.minus.com/je3SvPydQUFsp.png

Where I think the 2 parts are split by x=2. From x=0 to x=2 I see a disc method and then from x =2 to x=4 I see the washer method. However because the disc/washer method is perpendicular to the axis of rotation (y) that means that the thicknes of the disc/washers will be dy, which means the limits of integration would be in terms of y. Therefore I don't see how I can set it up with 2 equations with different integrals.
 
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The volume is formed by rotation about the x-axis. The disks/washers should be vertical, not horizontal.

They should be washers for this problem.
 
SammyS said:
The volume is formed by rotation about the x-axis. The disks/washers should be vertical, not horizontal.

They should be washers for this problem.

Sorry it is about the y-axis , it was a mistype in the question on my part.
 

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