Finding Work from Angle, Mass, and Displacement

Click For Summary
SUMMARY

The discussion centers on calculating the work done by a flight attendant pulling a 73.8 N flight bag over a distance of 306 m at a constant velocity. The force exerted is 42.4 N at an angle of 60.1° above the horizontal. The correct formula for work is W = Fx * ∆X, where Fx is the horizontal component of the force. The final calculation yields a work value of 6437 J, confirming the proper application of the work formula.

PREREQUISITES
  • Understanding of basic physics concepts such as force, work, and displacement.
  • Familiarity with trigonometric functions, specifically cosine for resolving forces.
  • Knowledge of vector components in physics.
  • Ability to perform unit conversions and calculations in joules (J).
NEXT STEPS
  • Study the concept of work-energy principle in physics.
  • Learn how to resolve forces into their components using trigonometric functions.
  • Explore practical applications of work calculations in real-world scenarios.
  • Review problems involving constant velocity and forces at angles for deeper understanding.
USEFUL FOR

Students in physics, educators teaching mechanics, and anyone interested in understanding the principles of work and energy in physical systems.

Joel M
Messages
4
Reaction score
0

Homework Statement


A flight attendant pulls her 73.8 N flight bag
a distance of 306 m along a level airport floor
at a constant velocity. The force she exerts is
42.4 N at an angle of 60.1◦ above the horizon-
tal.
a) Find the work she does on the flight bag.
Answer in units of J.

Homework Equations


W=Fx * ∆X

The Attempt at a Solution


42.2Cos60.1=Fx=21.036
21.036*42.2=Work?

I found the displacement in the X direction and multiplied by total displacement to get work. This doesn't seem right to me. Any help?
 
Last edited:
Physics news on Phys.org
Welcome to PF!

Hi Joel M! Welcome to PF! :smile:

(have a delta: ∆ and try using the X2 tag just above the Reply box :wink:)
Joel M said:
42.2Cos60.1=Fx=21.036
21.036*42.2=Work?

I found the displacement in the X direction and multiplied by total displacement to get work. This doesn't seem right to me.

hmmm … :confused:

and what happened to the 306? :wink:
 


tiny-tim said:
Hi Joel M! Welcome to PF! :smile:

hmmm … :confused:

and what happened to the 306? :wink:

Oh, thanks got it now. (42.2)Cos(60.1)(306) = 6437J
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
18
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
3
Views
2K