How to find he coefficient of kinetic friction?

[snash1057]

A flight attendant pulls her 70.0 N flight bag a distance of 269 m along a level airport floor at a constant speed. The force she exerts is 32.0 N at an angle of 52.0° above the horizontal.

(a) Find the work she does on the flight bag.
_5299_J

(b) Find the work done by the force of friction on the flight bag.
_-5299_ J
(c) Find the coefficient of kinetic friction between the flight bag and the floor.
____

i found part A, by 32.0 x 269 x cos(52.0) = 5299J

but i don't understand how to get part c

i keep doing 32Cos(52)=70-32sin(52)k and i get .1357, don't get what I am doing wrong HELP!??

 

[256bits]

What is the matter with the value .1357?

 

[snash1057]

the answer is .4397

 

[SammyS]

What is the normal force the floor exerts on the flight bag?

Draw a Free Body Diagram.