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## Homework Statement

Hi,

If x^2+1=y/(x-y'), where y'=dy/dx, find dy/dx

I have tried so many ways, but I cannot seem to get the correct answer.

The answers I have got previously are:

i)

x² + 1 = y/(x - y')

(x² + 1)(x - y') = y

x(x² + 1) - y'(x² + 1) = y

x(x² + 1) - y = y'(x² + 1)

**dy/dx = x - y/(x² + 1)**

ii)

Switch divisors:

x – dy/dx = y / (x² + 1)

Now switch sides:

dy/dx = x - y / (x² + 1)

**dy/dx= (x³ + x – y) / (x² + 1)**

However, both of them do not seem correct.

Please help!

Any suggestions are welcome.

Also, I think that this is a linear ode. Even if i was to think of this as separable function, I would not have a clue how to get y' on the other side, as I would have to expand the left side with (x-y').

Ta