- #1

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3tany - dy/dx(secx) = 0"

This is what I set up:

3tany dx = secx dy

1/secx dx = 1/3tany dy

cosx dx = 1/3tany dy

[int] cosx dx = [int] 1/3tany dy

sinx = (1/3)ln|sinx|

I'm stuck as to what to do next, how to solve the equation.. did I mess up in the beginning or what am I doing wrong?