First order ODE, The Homogeneous Method.

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Homework Help Overview

The discussion revolves around solving a first-order ordinary differential equation (ODE) using the homogeneous method. The original poster presents a problem involving a substitution approach to simplify the equation.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various substitutions, including v = x/y and v = y/x, and their implications on the derivative dy/dx. There are attempts to manipulate the equation into a separable form, with some participants questioning the validity of their substitutions and the steps taken.

Discussion Status

The discussion is ongoing, with participants providing feedback on each other's approaches. Some guidance has been offered regarding algebraic manipulation to achieve a separable form, but there is no explicit consensus on the best method to proceed.

Contextual Notes

There are indications of confusion regarding the substitutions and their equivalence, which may affect the interpretation of the problem. Participants are exploring different algebraic techniques to clarify their approaches.

knowlewj01
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Homework Statement



[tex]\frac{1}{xy}[/tex] [tex]\frac{dy}{dx}[/tex] = [tex]\frac{1}{(x^2 + 3y^2)}[/tex]


Homework Equations



used the substitutions:

v = [tex]\frac{x}{y}[/tex] ,and
[tex]\frac{dy}{dx}[/tex] = [tex]v + x[/tex] [tex]\frac{dv}{dx}[/tex]

The Attempt at a Solution



took out a factor of xy on the denominator of the term on the right hand side and multiplied through by xy, made the substitutions and at the moment I have something that looks like this:

[tex]\frac{1}{v + 3/v}[/tex] = v + x [tex]\frac{dv}{dx}[/tex]

as it stands I can't see a way to do this by separation of variables, is it solvable by integrating factor? anyone got any ideas?
 
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You used the substitution v = x/y, but your work in calculating dy/dx looks like you started with y = vx, which is not equivalent to v = x/y.
 
ah thanks, i'll give it another go.
 
I was able to get the equation separated with the substitution v = y/x.
 
I have the substitutions:

v = [tex]\frac{y}{x}[/tex]

[tex]\frac{dy}{dx}[/tex] = v + x [tex]\frac{dv}{dx}[/tex]

so now my equation looks a bit like this:

[tex]\frac{1}{1/v + 3v}[/tex] = v + x [tex]\frac{dv}{dx}[/tex]

I played with it a bit and still can't see how to separate it, can anyone point me in the right direction?

thanks
 
What you have is fine, but needs cleaning up using ordinary algebra techniques.

  1. Rewrite 1/(1/v + 3v)) as a rational expression - one numerator and one denominator, with no fractions in the top or bottom.
  2. Subtract v from both sides, so that you have x*dv/dx on one side, and a rational expression on the other.
  3. Divide both sides by x. You should now be able to move dv or dx so that everything in v or dv is on one side, and everything in x or dx is on the other. The equation is now separated, and you can integrate to find the solution.
 

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