First Partial Derivative of f(x,y)=arctan (y/x)

Click For Summary

Homework Help Overview

The discussion revolves around finding the first partial derivative of the function f(x,y) = arctan(y/x). Participants are exploring the concept of partial derivatives in the context of multivariable calculus.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Some participants question which variable the original poster intends to differentiate with respect to, highlighting the necessity of clarity in multivariable functions. Others suggest revisiting foundational calculus concepts related to derivatives of arctangent functions.

Discussion Status

The discussion is ongoing, with participants providing guidance on the need for clarity in the differentiation process. There is an emphasis on the expectation that the original poster should demonstrate some prior attempts or understanding before receiving assistance.

Contextual Notes

Participants note that the original poster has not specified the variable for differentiation, which is crucial for addressing the problem correctly. There is also a mention of the expectation for users to show some work or attempts in order to facilitate meaningful help.

teng125
Messages
416
Reaction score
0
f(x,y)=arctan (y/x).
may i know what is the first partial derivative of this??

thanx
 
Physics news on Phys.org
Go back to your first calculus textbook and re-study the method of finding the derivative of Arctg(x).
 
teng125 said:
f(x,y)=arctan (y/x).
may i know what is the first partial derivative of this??

thanx

First partial derivative with respect to what? You have to know which variable you are taking the derivative with respect to when you try to find the partial derivative of a function of several variables.
 
If you wish simply to get answers, go to www.quickmath.com it will do derivatives, integrals etc., for the above problem use http://www.hostsrv.com/webmab/app1/MSP/quickmath/02/pageGenerate?site=quickmath&s1=calculus&s2=differentiate&s3=advanced .

Those who would help you here will require that you post some work (anything, an attempt, even if it is wrong) before they will respond.
 
Last edited by a moderator:
This site is amazing! I'm in love!
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K