Fission vs. Fusion question (particle physics)

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The discussion focuses on calculating the energy released during nuclear fission and fusion reactions. For fission, 1 gram of U-235 splits into La-148 and Br-87, while for fusion, 0.5 grams of D2O and T2O produce He-4 and a neutron. Participants express confusion regarding the fusion process, particularly about the fate of the oxygen atoms and leftover deuterium after the reaction. There is a consensus that the question is complex, especially the fusion part, but it is noted that binding energies can be neglected. Clarification on the calculations and assumptions made in the fusion reaction is sought to accurately compare the energy outputs.
Diyon335
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Homework Statement
Calculate energy released in the reactions below, and compare them (see full question below)
Relevant Equations
a) FISSION: 1g of U-235 splits into La-148 + Br-87
b) FUSION: 0.5g of D2O with 0.5g of T20 creates He-4 and a neutron
useful equations: E = Δm(c^2)
Homework Statement: Calculate energy released in the reactions below, and compare them (see full question below)
Homework Equations: a) FISSION: 1g of U-235 splits into La-148 + Br-87
b) FUSION: 0.5g of D2O with 0.5g of T20 creates He-4 and a neutron
useful equations: E = Δm(c^2)

Hey, can someone help me with calculating the energies released by fission and fusion. Any help with a small explanation on WHY certain conversions and calculations are done would be so helpful, thank you!

The full question is this:

a) Calculate the energy released if 1 gram of U-235 splits into La-148 + Br-87.
b) Calculate the energy released in the fusion process of 0.5 grams of heavy water (D2O) with 0.5 grams of superheavy water (T2O), creating He-4 and a neutron. You may neglect the binding energies of the molecules.
c) Compare the energies released per gram. Which would you prefer?
 
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Can you please show your effort?
 
Diyon335 said:
useful equations: E = Δm(c^2)
If that is to be useful, what do you need to know?
 
It's kind of a messy question. The U235 part is not too bad. But the D2O/T2O part is way messy.

It says the D2O and T2O fuses to produce He-4 and "a neutron." Um... Ok, what happens to the O's? And what happens to the left-over D's? Because 0.5 gram of D2O has more molecules than 0.5 gram of T2O.

Maybe it means that the T's and the D's that match are used to produce a bunch of He-4's and the corresponding number of neutrons. And the O's get ignored? Or maybe the O's get included and converted to He-4? (Assuming it's all O-16, for simplicity.) And maybe the extra D's get converted to He-4? So one neutron per T, and the rest to He-4? Way messy question.
 
DEvens said:
It's kind of a messy question. The U235 part is not too bad. But the D2O/T2O part is way messy.

It says the D2O and T2O fuses to produce He-4 and "a neutron." Um... Ok, what happens to the O's? And what happens to the left-over D's? Because 0.5 gram of D2O has more molecules than 0.5 gram of T2O.

Maybe it means that the T's and the D's that match are used to produce a bunch of He-4's and the corresponding number of neutrons. And the O's get ignored? Or maybe the O's get included and converted to He-4? (Assuming it's all O-16, for simplicity.) And maybe the extra D's get converted to He-4? So one neutron per T, and the rest to He-4? Way messy question.
In defense of the full problem statement, it does say, "you may neglect the binding energies of the molecules," and, "... creating He-4 and a neutron."
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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