Fluid Equilibrium Interface Shape

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Hi PF!

Suppose a 2D rectangular channel with wall-normal perpendicular to the downward gravity force ##F## rests is static equilibrium. What shape would the liquid take?

Looking at the equations of motion, I think the following would have to be satisfied: $$\frac{d P}{dy} = -\rho F\\
\Delta P = \sigma k_1$$
1) Eulers equation for 1D (since gravity not in horizontal ##x##-direction)
2) Laplace pressure jump where ##\Delta P## is pressure jump from inside to outside liquid interface and 2D implies curvature ##k_2 = 0##, thus not listed.

Integrating Eulers eq yields ##P = -\rho F y + c##.

If we call the meniscus ##\Gamma(x)##, then it's curvature must be ##k_1(x) = \Gamma''(x) / (1+\Gamma(x)^2)^{3/2}##. Evaluating the pressure along the meniscus and applying the Laplace pressure jump implies $$\sigma \frac{\Gamma ''(x)}{(1+\Gamma'(x)^2 )^{3/2}} = \rho F \Gamma(x)$$ subject to $$\Gamma'(0) = -\cot \theta\\ \Gamma'(1) = 0$$ where I assume the channel has length 2. But how is this equation solved; the IC's are both at the first derivative.

For help purposes, seems like a good question for @Chestermiller and @boneh3ad though anyone's thoughts are welcomed.
 
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Chestermiller said:
I haven't rederived your equation to confirm that it is correct, but, of course, this 2nd order non-linear ODE with split boundary conditions can be solved numerically.
Thanks for checking it out! I have a question for you; I need an analytic solution in order to examine small linear normal oscillations. Then would you suggest a good approach is to get the numerical solution and curve-fit it, and use that? Or are there more sophisticated techniques?

I noticed this problem is a well understood problem and admits a closed analytic solution if I use as a BC ##\Gamma(\infty) \to 0##. Which is close to zero at ##\Gamma'(1)##.
 
joshmccraney said:
Suppose a 2D rectangular channel with wall-normal perpendicular to the downward gravity force ##F## rests is static equilibrium. What shape would the liquid take?

It's been a while since I worked on this kind of problem, but I suspect you are oversimplifying the system- for example, I'm not sure you can simply ignore the 3D aspect of the problem. I found some relevant results, hope these are helpful:

http://adsabs.harvard.edu/abs/2005PhyD..209..236Shttps://www.cambridge.org/core/jour...clined-plane/7AEF7AF42BC3311BB42A193FE6F44FE5https://pdfs.semanticscholar.org/59e8/b936dc64535a898064258dfb8bc052d01f7e.pdf
 
joshmccraney said:
Thanks for checking it out! I have a question for you; I need an analytic solution in order to examine small linear normal oscillations. Then would you suggest a good approach is to get the numerical solution and curve-fit it, and use that? Or are there more sophisticated techniques?

I noticed this problem is a well understood problem and admits a closed analytic solution if I use as a BC ##\Gamma(\infty) \to 0##. Which is close to zero at ##\Gamma'(1)##.
I'm not familiar with that analytic solution, but even if you know that, how would you then include oscillations.

I would start out by writing the PDE for the behavior with oscillations, then linearize with respect to the oscillations, and then separate that into the non-linear equation you have already plus the linearized equation for the oscillations (based on the nonlinear static equation solution). Then I would resolve the linearized equation into harmonics, which would reduce it to a sequence of uncoupled linear ODEs in the spatial coordinate.
 
Sorry for late reply!

Chestermiller said:
I'm not familiar with that analytic solution, but even if you know that, how would you then include oscillations.
The technique we use is to basically solve 5 linearized equations where velocity ##u## admits a potential ##\phi##. So we're inviscid, though we have viscous potential theory predictions as well. The 5 eqns are

$$
\nabla^2 \phi = 0 \,\,\, (\Omega)\\
\phi_n \cdot \hat n = 0 \,\,\,(\Sigma)\\
\int_\Gamma \phi_n = 0\,\,\,(\Gamma)\\
B[\phi_n] = 0 \,\,\, (\gamma)\\
-\phi_n''(s) - \cos^2\alpha \phi_n = \lambda^2 \phi \,\,\, (\Gamma)
$$
where ##\Omega## is liquid volume, ##\Sigma## is container walls, ##\Gamma## is equilibrium interface, ##\gamma## is equilibrium contact line, and ##\alpha## is equilibrium contact angle. Then those equations are continuity, no penetration, volume conservation, a contact line/angle condition defined by some operator ##B##, and a pressure balance among inertial pressure (linearized Bernoulli's) and Laplace pressure (linearized surface curvatures). A normal mode assumption in time is made, where the temporal component is ##\exp(i \lambda t)##.

Chestermiller said:
I would start out by writing the PDE for the behavior with oscillations, then linearize with respect to the oscillations, and then separate that into the non-linear equation you have already plus the linearized equation for the oscillations (based on the nonlinear static equation solution). Then I would resolve the linearized equation into harmonics, which would reduce it to a sequence of uncoupled linear ODEs in the spatial coordinate.

That sounds similar to what we've done, right? Clearly there is some difference since I end up with a single ODE rather than a system. Can you elaborate further or recommend literature here?
 
joshmccraney said:
Sorry for late reply!The technique we use is to basically solve 5 linearized equations where velocity ##u## admits a potential ##\phi##. So we're inviscid, though we have viscous potential theory predictions as well. The 5 eqns are

$$
\nabla^2 \phi = 0 \,\,\, (\Omega)\\
\phi_n \cdot \hat n = 0 \,\,\,(\Sigma)\\
\int_\Gamma \phi_n = 0\,\,\,(\Gamma)\\
B[\phi_n] = 0 \,\,\, (\gamma)\\
-\phi_n''(s) - \cos^2\alpha \phi_n = \lambda^2 \phi \,\,\, (\Gamma)
$$
where ##\Omega## is liquid volume, ##\Sigma## is container walls, ##\Gamma## is equilibrium interface, ##\gamma## is equilibrium contact line, and ##\alpha## is equilibrium contact angle. Then those equations are continuity, no penetration, volume conservation, a contact line/angle condition defined by some operator ##B##, and a pressure balance among inertial pressure (linearized Bernoulli's) and Laplace pressure (linearized surface curvatures). A normal mode assumption in time is made, where the temporal component is ##\exp(i \lambda t)##.
That sounds similar to what we've done, right? Clearly there is some difference since I end up with a single ODE rather than a system. Can you elaborate further or recommend literature here?
Sorry, but I don't follow your analysis. Maybe someone else can help.