Fluid Flow and Projectile Motion

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Water flows through a pipe with a radius of 1 inch at 2 m/s and exits through a nozzle with a radius of 1/4 inch, resulting in a velocity of 32 m/s at the nozzle. To determine how far the water travels horizontally before hitting the ground, the time of flight from a height of 2 meters is calculated to be approximately 0.64 seconds. Using the horizontal speed of 32 m/s, the horizontal displacement is found to be 20.4 meters. The discussion emphasizes the importance of understanding fluid dynamics and projectile motion principles to solve the problem accurately. The final answer indicates the water travels 20.4 meters horizontally before impact.
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Homework Statement


Water travels through a pipe with a radius of 1 inch at a speed of 2 m/s. There is a nozzle at the end of the pipe with a radius of 1/4 inch. The pipe is horizontal and 2m above the ground. How far does the water travel in the air before hitting the ground?

r1 = 1 in.
r2 = 1/4 in.
V1 = 2 m/s
y = 2 m

Homework Equations



A1V1=A2V2
A = ∏r2
Δx = Vxt

The Attempt at a Solution



I found that A1 = 3.14 in.2 and A2 = .20 in.2
I plugged those in and found V2 = 31.4 m/s2.

Now I think I have to find t so I can work with Δx = Vxt but I'm not sure how to go about that or if that's even the direction I should be taking.

EDIT: I tried using kinematics, re-arranging V2 = V0^2 + 2aΔx. I plugged my values into -V0^2 / 2a = Δx and got -31.42 / 2(9.81) = 50.3 m
Would that be correct?
 
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dropgigawatt said:
I found that A1 = 3.14 in.2 and A2 = .20 in.2

You did not have to. All you need is the ratio ## \frac {A_1} {A_2} = \frac { \pi r_1^2 } {\pi r_2^2 } = \left( \frac {r_1} {r_2} \right)^2 = 16 ##, so the velocity at the nozzle is 32 m/s exactly.

I plugged those in and found V2 = 31.4 m/s2.

The result is inaccurate, and the dimension is wrong.

Now I think I have to find t so I can work with Δx = Vxt but I'm not sure how to go about that or if that's even the direction I should be taking.

The rest of the problem is simple projectile motion. You know the initial velocity and the initial height. Find where it strikes the ground.
 
The water is traveling both horizontally and vertically. They want you to find how far it travels horizontally when it hits the ground. How long does it take for an object dropped from a height of 2 m to reach the ground? How far does an object travel horizontally in that amount of time if its horizontal speed is 32 m/s?
 
I got it.
t = .64 s
displacement = 32(.64) = 20.4 m

Thanks guys!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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