Calculating Pressure Change in a Manometer Due to Removal of Air Bubble

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SUMMARY

The discussion centers on calculating the change in mercury height in a manometer after the removal of a 3 cc air bubble and 3 cc of oil from one leg. The relevant equation used is Δp = ρgh, where ρ represents the density of the fluid, g is the acceleration due to gravity, and h is the height change. The user calculated the length of the air bubble column to be 2.445 cm but struggled to proceed further. The solution requires understanding the pressure change caused by the removal of the air bubble and oil.

PREREQUISITES
  • Understanding of fluid mechanics principles
  • Familiarity with manometer operation and applications
  • Knowledge of specific gravity and its implications
  • Proficiency in using the equation Δp = ρgh
NEXT STEPS
  • Study the effects of specific gravity on fluid pressure in manometers
  • Learn how to calculate pressure changes in fluid systems using Δp = ρgh
  • Explore the concept of hydrostatic pressure in different fluid columns
  • Investigate the behavior of gas bubbles in liquid columns
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Students in physics or engineering courses, particularly those studying fluid mechanics, as well as professionals involved in pressure measurement and fluid dynamics.

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Homework Statement


a manometer consisting of tube that is 1.25 cm inner diameter . on one side , the manometer leg contains mercury,10cc of an oil(S.G.=1.4)and 3 cc of air as a bubble in oil . the other leg contains only mercury . both legs are open to atmosphere and static . An accident occurs in which 3cc of oil and air bubble are removed from one leg . how much do mercury height levels change?



Homework Equations


Δp=ρgh


The Attempt at a Solution


i calculated the change in pressure due to 3 cc air bubble
∏/4 * 1.25*1.25*l=3
where l = length of airbubble column
l=2.445 cm ...after that cudnt proceed

please help me how to do it asap
 
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