Fluid Mechanics Newtons law of viscosity

wozzers
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Homework Statement


having problems differentiating


Homework Equations


Tw ( wall shear stress)= -U(viscosity)*du/dr
been given u as 2V(1-(r/r)^2)


The Attempt at a Solution


i substituted u in and got

d/dr (2V(1-(r/r)^2)
i tried to multiply out the minus sign and 2V and got a very different answer i got -2V+2V (r/r)^2

when the answer is supposed to be -4VR/R^2

please help
 
on Phys.org
What do you mean here:

been given u as
2V(1-(r/r)^2) = 2V(1 - 1) = 0

?
 
wozzers said:

Homework Statement


having problems differentiating


Homework Equations


Tw ( wall shear stress)= -U(viscosity)*du/dr
been given u as 2V(1-(r/r)^2)

Do you mean
[tex] u = 2V\left(1 - \left(\frac{r}{r_0}\right)^2\right)[/tex]
where [itex]r_0[/itex] is the radius of what I assume to be a cylindrical pipe?


The Attempt at a Solution


i substituted u in and got

d/dr (2V(1-(r/r)^2)
i tried to multiply out the minus sign and 2V and got a very different answer i got -2V+2V (r/r)^2

when the answer is supposed to be -4VR/R^2

please help

The given answer is for [itex]du/dr[/itex]; to get [itex]T_w[/itex] you have to multiply that by [itex]-\mu[/itex].

So far all you've done is multiply [itex]u[/itex] by -1. Try differentiating with respect to r first.
 
r=R and its (r/R)^2
 
okay now i have differentiated it with respect to r i get 2V2r/R^2) or -(4Vr/R^2) thanks again i was then required to use the wall shear stress to determine the frictional force but it is very straight forward from there
 

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