Fluid mechanics of floating wood

Click For Summary

Homework Help Overview

The discussion revolves around a fluid mechanics problem involving a piece of wood floating in water within a bottle connected to an air pump. The participants explore how increasing air pressure affects the buoyancy and submersion of the wood.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss Archimedes' principle and the forces acting on the floating object. They question how increased air pressure might influence the volume and mass of the wood, as well as its buoyancy.

Discussion Status

The conversation is ongoing, with participants providing insights into the relationship between pressure, buoyancy, and the forces acting on the wood. There is a focus on clarifying concepts rather than reaching a consensus.

Contextual Notes

Some participants express uncertainty about the effects of air pressure on the wood, indicating a need for more information regarding the material properties of wood under pressure.

utkarshakash
Gold Member
Messages
852
Reaction score
13

Homework Statement


A piece of wood is floating in water kept in a bottle. The bottle is connected to an air pump. Neglect the compressibility of water. When more air is pushed into the bottle from the pump, the piece of wood will float with

a)larger part in the water
b)lesser part in the water
c)same part in the water
d)it will sink

Homework Equations



The Attempt at a Solution


When more air is pushed the air pressure inside the bottle increases. But what will be its effect on floatation?
 
Physics news on Phys.org
I'm not sure it's possible to answer this exactly without more knowledge of how wood responds to changes in air pressure. But I think they're trying to get you to consider what determines the volume of the block that's submerged. Can you state Archimedes' principle?
 
haruspex said:
I'm not sure it's possible to answer this exactly without more knowledge of how wood responds to changes in air pressure. But I think they're trying to get you to consider what determines the volume of the block that's submerged. Can you state Archimedes' principle?

The liquid exerts a pressure on the solid immersed which is equal to the weight of the displaced fluid.
 
utkarshakash said:
The liquid exerts a pressure on the solid immersed which is equal to the weight of the displaced fluid.
Shouldn't say pressure there. It exerts that force (upwards). Pressure is force per unit area.
When an object is floating, at rest, what force would that be equal to?
 
haruspex said:
Shouldn't say pressure there. It exerts that force (upwards). Pressure is force per unit area.
When an object is floating, at rest, what force would that be equal to?

Weight of the displaced fluid which is equal to (Density of liq.*vol of solid immersed*g)
 
utkarshakash said:
Weight of the displaced fluid which is equal to (Density of liq.*vol of solid immersed*g)
True, but what I meant was, what other force is it equal to?
 
haruspex said:
True, but what I meant was, what other force is it equal to?

Its own weight.(Mass*g)
 
Right. Now, what will the increased air pressure do to the mass and volume of the wood?
 
haruspex said:
Right. Now, what will the increased air pressure do to the mass and volume of the wood?

Nothing:biggrin:
 
  • #10
utkarshakash said:
Nothing:biggrin:
Well, it won't change the mass, but it might squeeze it a bit.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 74 ·
3
Replies
74
Views
16K
  • · Replies 13 ·
Replies
13
Views
12K
Replies
7
Views
3K
Replies
1
Views
6K
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K