Solving Fluid Mechanics Question: Radial Gate Forces and Direction

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SUMMARY

The discussion focuses on calculating the forces acting on a radial gate in fluid mechanics, specifically for a gate with a radius of 6m and a length of 8m. The approach involves determining the horizontal force (Fh) using the formula Fh = ρgh and the vertical force (Fv) using Fv = ρgV, where V is the volume of water above the gate. Since there is no water above the gate in this scenario, Fv equals zero, leading to a resultant force direction of zero degrees. The solution requires breaking the load into horizontal and vertical components and integrating pressure along the gate's surface.

PREREQUISITES
  • Understanding of fluid mechanics principles, specifically hydrostatic pressure.
  • Familiarity with the concepts of force decomposition into horizontal and vertical components.
  • Knowledge of integration techniques for calculating pressure over a surface area.
  • Proficiency in trigonometry for determining resultant forces and angles.
NEXT STEPS
  • Study the application of hydrostatic pressure in fluid mechanics, focusing on radial gates.
  • Learn about the integration of pressure over curved surfaces in fluid dynamics.
  • Explore trigonometric methods for resolving forces in engineering applications.
  • Review past exam papers on fluid mechanics to understand common problem-solving approaches.
USEFUL FOR

Civil engineering students, particularly those in their second year, as well as professionals involved in hydraulic engineering and fluid mechanics applications.

AshNZ
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Hey guys,

I'm new here. I've been following PF on and off to get some hints in past but this is the first time I'm posting. I'm doing civil engineering second year and the following is an assignment question (there are total of four questions and I'm stuck on all four :( ). I'm not looking for direct answers but any hints would be great.

Q: Radial gate has a radius of 6m. It has length of 8m and can rotate about a hinge. What's total force on the hinge and its direction?The book I usually refer to uses the following procedure:
First they find Fh using rho*g*h
Then they find Fv using rho*g*V where V is the volume of water above the surface of the surface of the gate. And then they go on to some other formulas but I'm stuck at this point because in this particular question there is no water above the surface of the gate, which makes Fv = 0 (which inevitably leads to resultant force's direction of zero degrees in later stages)

I could be knocking on the door of the answer or I could be in the other city. Any help will be appreciated.
 
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I've cracked this question. There was a similar question in past years exam papers and luckily I had the solution for that paper.
 
I am assuming for anyone in the future searching for this thread...

You break the load into two components, one horizontal, and one vertical. You then integrate the pressure \rho g h along with the equation for a circle to get the total load in each direction?
 
Yes, you break it down to horz and vertical. Then find horizontal by rho*g*h*A(projected area). Then you find vertical using )(pi*r^2L)/4)*rho*g. Then use trig to find resultant and the angle.
 

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