1. The water in a tank is at a gauge pressure of 267,018 Pa. If the bottom of the tank that has an area of 0.8 m2, what is the force on the bottom of the tank? 2. P=F/A; F=P*A 3. Converted Pa into 38.8psi for P (267,018/6890); Converted the Area into 103.7 in^2 (.8*10.8*12); Multiply [P*A] 38.8 * 103.7 = 4023.6 in lbs = 335.3 lbs of force. Did I do this right?