This question has been asked several times, but I don't want the answer (I can see the stupid answer...) I need help with my solution...(adsbygoogle = window.adsbygoogle || []).push({});

1. The problem statement, all variables and given/known data

A large aquarium of height 5.00m is filled with fresh water to a depth of 2.00m. One wall of the aquarium consists of thick plastic 8.00m wide. By how much does the total force on that wall increase if the aquarium is next filled to a depth of 4.00m.

2. Relevant equations

p = ρgh

p = F/A

A = hw

3. The attempt at a solution

ρ = 0.998x10^{3}kg/m^{3}

g = 9.81 m/s^{2}

h_{1}= 2.00m

h_{2}= 4.00m

w = 8.00m

ΔF = F_{2}- F_{1}

ΔF = p_{2}A_{2}- p_{1}A_{1}

ΔF = ρgh_{2}A_{2}- ρgh_{1}A_{1}

ΔF = ρg (h_{2}A_{2}- h_{1}A_{1})

ΔF = ρg (h_{2}^{2}w - h_{1}^{2}w)

ΔF = ρgw (h_{2}^{2}- h_{1}^{2})

ΔF = (.998x10^{3}kg/m^{3}) (9.81 m/s^{2}) (8.00m) [ (4.00m)^{2}- (2.00m)^{2}]

ΔF = 9.40x10^{5}N

Correct Answer: 4.71x10^{5}N

Why am I double what the answer is suppose to be?

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# Fluids at Rest: Pressure/Force Problem

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