The discussion focuses on calculating the increase in total force on a wall of a large aquarium when the water depth is doubled from 2.00m to 4.00m. The relevant equations include pressure calculation using p = P0 + Dgh and force calculation with F = PA. The density of fresh water is a critical factor in determining the pressure exerted on the wall. The solution approach suggested involves using average pressure rather than integration to simplify the calculation.
PREREQUISITESStudents studying fluid mechanics, engineers designing aquariums, and anyone interested in the principles of pressure in fluids.
Okay. How about using the average pressure exerted on the wall instead?auk411 said:Homework Statement
A large aquarium of height 5.00m is filled with fresh water to a depth of 2.00m. One wall of the aquarium consists of thick plastic of 8.00m wide. By how much does the total force on that wall increase if the aquarium is next filled to a depth of 4.00m.
D= density
Homework Equations
p = P0 + Dgh
F=PA
The Attempt at a Solution
?
Not supposed to use Integration.