Fluids Mass Balance Integral Question | Homework Statement Explained

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SUMMARY

The discussion centers on the application of mass balance equations in fluid dynamics, specifically focusing on the integral form of the mass balance equation. The integral in question is \frac{d}{d\,t}(\int_{vol}\rho A_b\,dh) + \int{surf}\rho\sqrt{2gh}\,dA = 0, where the term \sqrt{2gh} is pulled through the integral due to the fact that 'h' varies with time but not with the area 'A'. This manipulation is confirmed as valid by participants in the discussion.

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Saladsamurai
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Homework Statement



I have include the schematic for visual purposes only. My question is about an integral, so a knowledge of Fluids is not necessarily required to answer my question.

Picture1-40.png



Homework Equations



This is the mass balance in a form that is suitable for this problem:

[tex]\frac{d}{d\,t}(\int_{vol}\rho\,dV) + \int_{surf}\rho(\mathbf{v}\cdot\mathbf{n})d\,A = 0[/tex]

Now the integral that I am concerned with is this next line of the above:

[tex]\frac{d}{d\,t}(\int_{vol}\rho A_b\,dh) + \int{surf}\rho\sqrt{2gh}\,dA = 0[/tex]

Now, in the solution, in the 2nd term, they 'pulled' [itex]\sqrt{2gh}[/itex] through the integral.

I know that 'h' varies with 't' but it does not vary with 'A.' This is why they did that right?

I am just trying to see why that was legal, but I think that I get it. Just another case of
me 'thinking out loud' again. :redface:
 
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Saladsamurai said:
Now, in the solution, in the 2nd term, they 'pulled' [itex]\sqrt{2gh}[/itex] through the integral.

I know that 'h' varies with 't' but it does not vary with 'A.' This is why they did that right?

Yes, you got it. :smile:
 
Thank you! :smile:
 

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