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Flux of Electric Field through a cone
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[QUOTE="Moara, post: 6252948, member: 659579"] [B]Homework Statement:[/B] A conic surface is placed Inside a region filled with uniform Electric Field E. The field lines are perpendicular to the geratrix AB. The cone has height h and radius R of it's base. Find the electric flux through the lateral surface of the cone. [B]Relevant Equations:[/B] Ø=E.S.cosx Øtot=qint/€ (gaus law) Since there is no charge inside the cone, the total flux through its surface is zero, hence Ø(lateral surface)+∅(base surface)=0. But ∅(base surface)=E.πR².cosΩ, because electric Field is homogenous. But by the figure, Ω is just arctg(h/R). So Ø(lateral surface)=-E.π.R².R/√(R²+h²). This is not the answer according to the solution I saw. My point is, does anyone could show me where is my mistake?[ATTACH=full]251822[/ATTACH] [/QUOTE]
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Flux of Electric Field through a cone
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