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How do I find the flux of the vector field F = (1,1,1) down through the surface [tex]\sigma[/tex], given by z = [tex]\sqrt{x^2+y^2}[/tex] and 1 < z < 2. The answer is 3pi but have no idea how to get it. I got it down to[tex]\int\int_R[/tex] x+y/[tex]\sqrt{x^2+y^2}[/tex] +1 dA. Now what?

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# Flux of the vector field F = (1,1,1)

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