Flux Through Concentric Spheres with Varying Charge Density

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SUMMARY

The discussion focuses on calculating the electric flux through a larger sphere with a varying charge density defined by ρ = Ar², where A is a constant. The key conclusion is that the flux through the larger sphere is determined by the total charge enclosed within the inner sphere, which requires integrating the charge density. According to Gauss' Law, the total flux can be directly obtained from the net charge without needing to calculate the electric field explicitly.

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  • Understanding of Gauss' Law in electrostatics
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  • Knowledge of charge density functions and integration techniques
  • Basic concepts of electric fields and their relationship to charge
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Homework Statement


A sphere of radius a has its center at the origin and a charge density given by p=Ar^2 where A=constant. Another sphere of radius 2a is concentric with the first. Find the flux through the larger sphere.

Homework Equations


Flux=E*da

The Attempt at a Solution


According to my textbook, flux is independent of the radius. It depends on the charge enclosed by the sphere. So regardless, the flux is the same for both. We know flux is determined by the field magnitude and area. The area is 4piR^2 and the field magnitude is given by (1/4pi(eo))(q/R^2)
Multiplying the two gives us that flux is the charge divided by eo.
The flux should then be Ar^2/eo r being a Aa^2/eo

I feel like I'm missing an important concept.
 
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SarahAlbert said:
The flux should then be Ar^2/eo r being a Aa^2/eo
That's not correct. What is the net charge enclosed by the larger sphere?
 
You need to find the total charge on the inner sphere (integrating the the charge density).
Then this also the charge enclosed by the outer sphere and Gauss' Law will immediately
give you the total flux.(you don't need to use the electric field E)
 

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